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laila [671]
3 years ago
9

When placing a fulcrum in a lever, to get the greatest mechanical advantage, you would need to make the length of the effort arm

greater than the length of the load arm. Why?
Chemistry
1 answer:
son4ous [18]3 years ago
4 0
<span>A machine is a device that does work. Most machines consist of a number of elements, such as gears and ball bearings, that work together in a complex way. Nonetheless, no matter how complex they are, all machines are based in some way on six types of simple machines. These six types of machines are the lever, the wheel and axle, the pulley, the inclined plane, the wedge, and t</span>
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What happens to the electrons in an ionic bond?
Anton [14]

Answer:

In an ionic bonds, the metal loses electrons to become a positively charged cation, In which the nonmetal accepts those electrons to become a negatively charged anion.

Explanation:

3 0
3 years ago
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What is the ratio of hydrogen(H) to oxygen(O) in hydrogen peroxide(H2O2)?
Alona [7]

Answer: 2:2 but if simplified it’s 1:1

Explanation:

7 0
3 years ago
Match the scientists to their contributions to the development of the periodic table.
zloy xaker [14]

Answer:

1. Dmitri Mendeleev

2. Johann Dobhereiner

3. John Newlands

4. Henry Moseley

If you find this helpful please give me Brainliest award

4 0
3 years ago
10.0 g of calcium carbonate was heated. The mass of calcium oxide left was 5.6 g. Calculate the mass of
Kipish [7]

Answer:

4.4g

Explanation:

Mass of CaCO3 = 10g

Mass of CaO = 5.6g

Mass of CO2 =?

Mass of CaCO3 = Mass of CaO + Mass of CO2

Mass of CO2 = Mass of CaCO3 — Mass of CaO

Mass of CO2 = 10 — 5.6

Mass of CO2 = 4.4g

4 0
3 years ago
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A 0.1326 g sample of magnesium was burned in an oxygen bomb calorimeter. the total heat capacity of the calorimeter plus water w
Sladkaya [172]

Answer: Th enthalpy of combustion for the given reaction is 594.244 kJ/mol

Explanation: Enthalpy of combustion is defined as the decomposition of a substance in the presence of oxygen gas.

W are given a chemical reaction:

Mg(s)+\frac{1}{2}O_2(g)\rightarrow MgO(s)

c=5760J/^oC

\Delta T=0.570^oC

To calculate the enthalpy change, we use the formula:

\Delta H=c\Delta T\\\\\Delta H=5760J/^oC\times 0.570^oC=3283.2J

This is the amount of energy released when 0.1326 grams of sample was burned.

So, energy released when 1 gram of sample was burned is = \frac{3283.2J}{0.1326g}=24760.181J/g

Energy 1 mole of magnesium is being combusted, so to calculate the energy released when 1 mole of magnesium ( that is 24 g/mol of magnesium) is being combusted will be:

\Delta H=24760.181J/g\times 24g/mol\\\\\Delta H=594244.3J/mol\\\\\Delta H=594.244kJ/mol

4 0
3 years ago
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