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kramer
2 years ago
10

Classify the substances according to the strongest solute-solvent interaction that will occur between the given substances and w

ater during dissolution.
a. CuCl2
b. CuSO4
c. NH3
d. CH3OH
Chemistry
1 answer:
-BARSIC- [3]2 years ago
5 0

Explanation:

Ion-dipole interactions are defined as the interactions that occur when an ion interacts with the dipole of a molecule (polar molecule).

For example, CuCl_{2}, CuSO_{4}, CaCl_{2}, NaCl etc are all the molecules that will show ion-dipole interactions.

Dipole-dipole interactions are defined as the interactions that occur when partial positive charge on an atom is attracted by partial negative charge on another atom.

When a polar molecules produces a dipole on a non-polar molecule through distribution of electrons then it is known as dipole-induced forces.

For example, NH_{3}, CH_{3}OH etc are the molecules which show dipole-dipole interactions.

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Can someone PLEASE help me with this im struggling bad
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Answer:

  1. 4.5+2.34= 6.84
  2. 4.5-5 =-0.5
  3. 6.00+3.411= 9.411
  4. 3.4×2.32 = 7.888
  5. 7.77/2.3= 3.37

7. 1200×23.4=28080

9. = 78.512

10. =341.199

11= 7.45

12 =65.0023

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2 years ago
) If you prepared a solution by adding equal numbers of moles of sodium sulfite (Na2SO3) and sodium hydrogen sulfite (NaHSO3) to
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The pH of the solution is mathematically given as

PH=7.21

<h3>What would be the pH of the solution?</h3>

Question Parameters:

sodium hydrogen sulfite (NaHSO3) to 50 mL of water.

Generally, the equation for the Chemical Reaction for the acid dissociation  is mathematically given as

HSO3- + H2O ---> H3O+ + SO3^2-

Therefore

pH=Pka+log\frac{A-}{Ha}

A-=HA

pH=pKa

Since pKa NaHSO3=7.21

Hence, PH=7.21

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1 year ago
What is another name for a mole?
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3 years ago
An aqueous solution of a certain chemical is found to boil at 104.5 oC. At what temperature is this solution likely to freeze? T
xeze [42]

Answer:

16.4 °C

Explanation:

Boiling point elevation is the phenomenon in which the boiling point of a solvent will increase when another compound is added to it; meaning that athe resultant solution has a higher boiling point than its pure solvent.

Using the ebullioscopic constant,

ΔT = m * i * Kb

Where,

Δ T is the temperature difference between the boiling point of the solution, Temp.f and boiling point of the pure solvent, Temp.i

Kb is the ebulliscope factor of water = 0.510 °C.kg/mol

i is the van hoffs number = 1

m is the molality in mol/kg.

Calculating the molality of the solution,

Temp.i = 100°C

Temp.f = 104.5 °C

= 4.5/(1*0.510)

= 8.8235 mol/kg

Freezing point depression is defined as the decrease in the freezing point of a solvent on the addition of a solute.

Using the same equation, but kf = 1.86 °C.kg/mol

ΔT = m * i * Kf

Temp.i = freezing point of water = 0°C

Temp.f = (8.8235*1.86) - 0

= 16.412 °C

Freezing point of the solution = 16.4 °C

3 0
2 years ago
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