<span>The chemical caharacteristics of the compound is different their corresponding elements. Eg. H2 - Combustible and O2 - Supporter of combustion BUT Their compound H2O is incombustible as it po...</span>
Answer:
- 4.5+2.34= 6.84
- 4.5-5 =-0.5
- 6.00+3.411= 9.411
- 3.4×2.32 = 7.888
- 7.77/2.3= 3.37
7. 1200×23.4=28080
9. = 78.512
10. =341.199
11= 7.45
12 =65.0023
13.=3400210.34
Explanation:
please mark me as branliest
hope it is helpful
The pH of the solution is mathematically given as
PH=7.21
<h3>What would be the pH of the solution?</h3>
Question Parameters:
sodium hydrogen sulfite (NaHSO3) to 50 mL of water.
Generally, the equation for the Chemical Reaction for the acid dissociation is mathematically given as
HSO3- + H2O ---> H3O+ + SO3^2-
Therefore

A-=HA
pH=pKa
Since pKa NaHSO3=7.21
Hence, PH=7.21
For more information on Chemical Reaction
brainly.com/question/11231920
Answer:
16.4 °C
Explanation:
Boiling point elevation is the phenomenon in which the boiling point of a solvent will increase when another compound is added to it; meaning that athe resultant solution has a higher boiling point than its pure solvent.
Using the ebullioscopic constant,
ΔT = m * i * Kb
Where,
Δ T is the temperature difference between the boiling point of the solution, Temp.f and boiling point of the pure solvent, Temp.i
Kb is the ebulliscope factor of water = 0.510 °C.kg/mol
i is the van hoffs number = 1
m is the molality in mol/kg.
Calculating the molality of the solution,
Temp.i = 100°C
Temp.f = 104.5 °C
= 4.5/(1*0.510)
= 8.8235 mol/kg
Freezing point depression is defined as the decrease in the freezing point of a solvent on the addition of a solute.
Using the same equation, but kf = 1.86 °C.kg/mol
ΔT = m * i * Kf
Temp.i = freezing point of water = 0°C
Temp.f = (8.8235*1.86) - 0
= 16.412 °C
Freezing point of the solution = 16.4 °C