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uranmaximum [27]

2 years ago

15

Please help please and please actually answer please

2 answers:

SOVA2 [1]2 years ago

6 0

Answer:

#3

Step-by-step explanation:

Natali [406]2 years ago

5 0

Answer:

it's the last one

Step-by-step explanation:

last one

You might be interested in

If the original square had a side length of

irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas in the attached figure N 3, and the trinomial is $x^{2} +11x+28$

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

$Length=(x+4)\ in$

$width=(x+7)\ in$

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

$A1=(x)(x)=x^{2}\ in^2$

$A2=(4)(x)=4x\ in^2$

$A3=(x)(7)=7x\ in^2$

$A4=(4)(7)=28\ in^2$

The total area of the second rectangle is the sum of the four areas

$A=A1+A2+A3+A4$

State the product of (x+4) and (x+7) as a trinomial

$(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28$

Part c) If the original square had a side length of x = 2 inches, then what is the area of the second rectangle?

we know that

The area of the second rectangle is equal to

$A=A1+A2+A3+A4$

For x=2 in

substitute the value of x in the area of each portion

$A1=(2)(2)=4\ in^2$

$A2=(4)(2)=8\ in^2$

$A3=(2)(7)=14\ in^2$

$A4=(4)(7)=28\ in^2$

$A=4+8+14+28$

$A=54\ in^2$

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

$A(x)=x^{2} +11x+28$

For x=2 in

substitute and solve for A(x)

$A(2)=2^{2} +11(2)+28$

$A(2)=4 +22+28$

$A(2)=54\ in^2$ ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0

3 years ago

DerKrebs [107]

B. Y equals 0, because if you plug it in ( multiply 2 by 9 ) you will get 18-18 which equals 0.

6 0

3 years ago

Angle A and Angle B are supplementary. Angle A has a measure of 3x - 6 and Angle B has a measure of 54. What is the value of x?

Anni [7]

Answer:

44 degrees

Step-by-step explanation:

Since they are supplementary, they add up to 180. This means that

3x - 6 + 54 = 180

Solving,

3x + 48 = 180

subtract 48 from both sides

3x = 132

divide both sides by 3

x = 44 degrees

8 0

2 years ago

Solve for x.<br> 7(1x - 3) = 4(x + 5)

alexandr1967 [171]

Answer:

x = 41/3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS
Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

7(1x - 3) = 4(x + 5)

<u>Step 2: Solve for </u><em><u>x</u></em>

Simplify: 7(x - 3) = 4(x + 5)
Distribute: 7x - 21 = 4x + 20
Subtract 4x on both sides: 3x - 21 = 20
Add 21 on both sides: 3x = 41
Divide 3 on both sides: x = 41/3

<u>Step 3: Check</u>

<em>Plug in x to verify it's a solution.</em>

Substitute: 7(1(41/3) - 3) = 4(41/3 + 5)
Multiply: 7(41/3 - 3) = 4(41/3 + 5)
Subtract/Add: 7(32/3) = 4(56/3)
Multiply: 224/3 = 224/3

Here, we see that 224/3 is indeed equivalent to 224/3. ∴ x = 41/3 is a solution to the equation.

And we have our final answer!

6 0

2 years ago

Karen paid $43.70 for a book. The price of the book was $40 what wasvthe salesvtax r

Elden [556K]

3.70 was the tax price

8 0

3 years ago

Read 2 more answers