1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tpy6a [65]
3 years ago
5

Titaium oxside is often added to food to color it white. If a jelly bean contains approximately 1.28x10-5 moles of TiO2, how man

y grams of TiO2 are in a jelly bean
Chemistry
1 answer:
PIT_PIT [208]3 years ago
6 0

Answer:

1.02 × 10⁻³ g

Explanation:

Step 1: Given data

Number of moles of titanium (IV) oxide in 1 jelly bean (n): 1.28 × 10⁻⁵ moles

Step 2: Calculate the mass (in grams) corresponding to 1.28 × 10⁻⁵ moles of TiO₂

To convert moles to mass, we need a conversion factor. In this case, it is the molar mass of TiO₂: 79.87 g/mol.

1.28 × 10⁻⁵ mol TiO₂ × 79.87 g TiO₂/1 mol TiO₂ = 1.02 × 10⁻³ g TiO₂

You might be interested in
How many moles of oxygen atoms are in 2.79
Phantasy [73]

0.05 mol of oxygen atom.

Explanation:

Mass of potassium hydroxide = 2.79g

Unknown:

Number of moles = ?

Solution:

To solve this problem, find the number of moles of the potassium hydroxide.

  Number of moles of KOH = \frac{mass}{molar mass}

 Molar mass of KOH = 39 + 16 + 1 = 56g/mol

 Number of moles of KOH = \frac{2.79}{56} = 0.05mole

 Now,

      1 mole of KOH contains 1 mole of oxygen atom

      0.05 mole of KOH will have 0.05 mole of oxygen atom.

Learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

3 0
4 years ago
What is a correct expression of the law of conservation mass
nekit [7.7K]
Law of conservation of mass- The total mass after a chemical reaction is exactly the same as the mass before.
5 0
4 years ago
A cube of iron with dimensions of 3.0 cm by 3.0 cm by 3.0 cm has a mass of 212 grams. What
egoroff_w [7]

Answer:

7.85 g/cm³

Explanation:

Density is Mass/Volume

The mass is 212 grams

The volume is 27 cm³ (3 x 3 x 3 = 27)

212/27 = 7.851851852

We can estimate this to 7.85 g/cm³

8 0
3 years ago
A 420 mL sample of a 0.100 M formate buffer, pH 3.75, is treated with 7 mL of 1.00 M KOH. What is the pH following this addition
Art [367]

<u>Answer:</u> The pH of the resulting solution will be 3.60

<u>Explanation:</u>

Molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Moles}}{\text{Volume}} ......(1)

We are given:

Molarity of formic acid = 0.100 M

Molarity of potassium formate = 0.100 M

Volume of solution = 420 mL = 0.420 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

\text{Moles of formic acid}=(0.100mol/L\times 0.420L)=0.0420mol

\text{Moles of potassium formate}=(0.100mol/L\times 0.420L)=0.042mol

Molarity of KOH = 1.00 M

Volume of solution = 7 mL = 0.007 L

Putting values in equation 1, we get:

\text{Moles of KOH}=(1mol/L\times 0.007L)=0.007mol

The chemical equation for the reaction of formic acid and KOH follows:

                 HCOOH+KOH\rightleftharpoons HCOOK+H_2O

I:                   0.042     0.007       0.042

C:                -0.007    -0.007     +0.007

E:                  0.035         -           0.049

Volume of solution = [420 + 7] = 427 mL = 0.427 L

To calculate the pH of the acidic buffer, the equation for Henderson-Hasselbalch is used:

pH=pK_a+ \log \frac{\text{[conjugate base]}}{\text{[acid]}} .......(2)

Given values:

[HCOOK]=\frac{0.049}{0.427}

[HCOOH]=\frac{0.035}{0.427}

pK_a=3.75

Putting values in equation 2, we get:

pH=3.75-\log \frac{(0.049/0.427)}{(0.035/0.427)}\\\\pH=3.75-0.146\\\\pH=3.60

Hence, the pH of the resulting solution will be 3.60

6 0
3 years ago
A mixture of carbon dioxide and hydrogen gases is maintained in a 6.68 L flask at a pressure of 2.14 atm and a temperature of 19
matrenka [14]

Answer:

The mass of hydrogen gas in the mixture: <u>w₂ = 0.433 g</u>

Explanation:

<u>According to the ideal gas equation: </u>

for an ideal gas, P.V = n_{total}.R.T

and n_{total}= n_{1}+n_{2}

Here, P: total pressure of the gases = 2.14 atm  

V: total volume of the gases = 6.68 L

T: temperature = 19 °C = 19+273.15 = 292.15K        (∵ 0°C = 273.15K)

R:  gas constant = 0.08206 L·atm·K⁻¹·mol⁻¹

n_{total}: total number of moles of gases

<u>To calculate the total number of moles of gases</u>:

n_{total} = \frac{P.V}{R.T} = \frac{2.14 atm\times 6.68 L}{0.08206 LatmK^{-}mol^{-}\times 292.15K} = <u>0.5963 moles</u>

Let, the number of moles of carbon dioxide be n₁ and number of moles of hydrogen be n₂

<u>Given:</u> mass of carbon dioxide: w₁ = 16.8 g, mass of hydrogen: w₂ = ?g

molar mass of carbon dioxide: m₁ = 44.01 g/mol, molar mass of hydrogen: m₂= 2.016 g/mol

Therefore, n_{total}= n_{1}+n_{2} =  (w₁ ÷ m₁) + (w₂ ÷ m₂)

⇒ 0.5963 mol =  (16.8 g ÷ 44.01 g/mol) + (w₂ ÷ 2.016 g/mol)

⇒ 0.5963 mol =  (0.3817mol) + (w₂ ÷ 2.016 g/mol)

⇒ 0.5963 mol - 0.3817mol = (w₂ ÷ 2.016 g/mol)

⇒ 0.2146 mol = (w₂ ÷ 2.016 g/mol)

⇒ w₂ = 0.433 g

<u>Therefore, the mass of hydrogen gas in the mixture: w₂ = 0.433 g</u>

4 0
4 years ago
Other questions:
  • 7) How many grams of HCl will be produced with 16.2 grams of H2 and excess Cl2? H2 + Cl2 -&gt; 2HCl
    8·1 answer
  • The boiling temperature of water is so much higher than that of methane because water molecules are
    10·1 answer
  • Based upon the Aggie Honor System Rules and the Academic Integrity statement on the CHEM 111/112/117 syllabus, assess whether th
    6·1 answer
  • How do I balance chemical equations?
    14·1 answer
  • Identify three elements and three compounds. How are they similar? How are they different?
    6·1 answer
  • How many molecules are there in 6.8 miles of carbon monoxide gas
    10·1 answer
  • What is the molar mass of AuCl3
    11·2 answers
  • According to the particle theory of matter, what is the difference between ice and water?
    9·1 answer
  • PLS HELP ME WITH MY ASSIGNMENT WILL MARK BRAINLIEST!
    9·2 answers
  • a student requires to prepare 500ml of 0.1M potassium dichromate (vii) from 0.250M solution must be diluted to 500ml​
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!