How many gallons of a 50% antifreeze solution must be mixed with 80 gallons of 30% antifreeze to get a mixture that is 40% a
ntifreeze? Use the six-step method.
You need ___ gallons.
1 answer:
I don't know what the "six-step method" is, but I do know how to solve the problem:
Let x = number of gallons of 50% solution
amount of antifreeze in 50% solution = 0.50x
amount of antifreeze in 10% solution = 0.10(80) = 8
amount of 40% solution = 0.40(x+80) = 0.40x + 32
Then, 0.50x + 8 = 0.40x + 32
0.10x = 24
x = 240 gal
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