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aev [14]
3 years ago
13

How many atoms are in 1.7 mols of CHF3

Chemistry
1 answer:
erastovalidia [21]3 years ago
5 0

Given :

Number of moles of CHF₃ is 1.7 .

Solution :

We know, 1 mole of any complex contains 6.022 × 10²³ molecules.

Let, 1.7 moles of CHF₃ contains n numbers of molecules.

So, n = 1.7 × 6.022 × 10²³ molecules

n = 10.2374 × 10²³ molecules

n = 1.0237 × 10²³ molecules

Hence, this is the required solution.

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A

Explanation:

because it loses 2 electrons

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Which one of the following solutions would have a pH value greater than 7?
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The 2 one

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What effect does the transfer of electrons have on the nuclei of the atoms involved?
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En un recipiente cerrado y rígido se introdujo una mezcla gaseosa a cierta temperatura y las presiones parciales de cada gas son
valkas [14]

Answer:

Qp > Kp, por lo tanto, la presión parcial de BrF₃(g) aumenta hasta alcanzar el equilibrio.

Explanation:

Paso 1: Escribir la ecuación balanceada

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Paso 3: Sacar una conclusión

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7 0
3 years ago
Calculate δg o for each reaction using δg of values:(a) h2(g) + i2(s) → 2hi(g) kj (b) mno2(s) + 2co(g) → mn(s) + 2co2(g) kj (c)
steposvetlana [31]
Part (a) :
H₂(g) + I₂(s) → 2 HI(g)
From given table:
G HI = + 1.3 kJ/mol
G H₂ = 0
G I₂ = 0
ΔG = G(products) - G(reactants) = 2 (1.3) = 2.6 kJ/mol

Part (b):
MnO₂(s) + 2 CO(g) → Mn(s) + 2 CO₂(g)
G MnO₂ = - 465.2
G CO = -137.16
G CO₂ = - 394.39
G Mn = 0
ΔG = G(products) - G(reactants) = (1(0) + 2*-394.39) - (-465.2 + 2*-137.16) = - 49.3 kJ/mol

Part (c):
NH₄Cl(s) → NH₃(g) + HCl(g)
ΔG = ΔH - T ΔS
ΔG = (H(products) - H(reactants)) - 298 * (S(products) - S(reactants))
      = (-92.31 - 45.94) - (-314.4) - (298 k) * (192.3 + 186.8 - 94.6) J/K
      = 176.15 kJ - 84.78 kJ = 91.38 kJ 
 





 
6 0
3 years ago
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