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harkovskaia [24]
3 years ago
14

Atoms that have lost or gained one or more electrons are called ________.

Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
3 0
Atoms that have lost or gained one or more electrons are called ions.
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Which of the following contains The greatest number of representative particles: 1 mole of water molecules, 1 mole of copper ato
Crazy boy [7]

Answer:

1 mole of sodium chloride ions

Explanation:

i hope this answer helps u

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7 0
3 years ago
If 0.250 mol of hydrogen gas occupies 0.333L at 20.0c what is the pressure in atmospheres?
maria [59]

Answer: The pressure will be 18.05 atm.

Explanation: Expression for ideal gas equation is :

PV=nRT

where,

P = Pressure of the gas = ? atm

V = Volume of the gas = 0.333L

n = Number of moles of gas = 0.250 moles

R = Universal gas constant = 0.082057\text{ L atm }mol^{-1}K^{-1}

T = temperature of the gas = 20°C = (273 + 20)K = 293K

Putting values in above equation, we get:

P\times 0.333L=0.250mol\times 0.082057\text{ L atm }mol^{-1}K^{-1}\times 293K

P = 18.05 atm

8 0
4 years ago
What is the h+ of a solution with a ph of 5.6
7nadin3 [17]
Just have to do antilog

[H+]= 10^-5.6
6 0
3 years ago
3. Balance each of the following redox reactions in the listed aqueous environment. (4 pts each, 8 pts total) Crs)NO3 (a) Cr (a)
GrogVix [38]

Explanation:

(a)   The given reaction equation is as follows.

        Cr(s) + NO^{-}_{3}(aq) \rightarrow Cr^{3+}(aq) + NO(g) (acidic)

So, here the reduction and oxidation-half reactions will be as follows.

Oxidation-half reaction: Cr(s) \rightarrow Cr^{3+}(aq) + 3e^{-}

Reduction-half-reaction: NO^{-}_{3} + 3e^{-}(aq) \rightarrow NO(g)

As total charge present on reactant side is -1 and total charge present on product side is +3. And, since it is present in aqueous medium. Hence, we will balance the charge for this reaction equation as follows.

      Cr(s) + NO^{-}_{3}(aq) + 4H^{+}(aq) \rightarrow Cr^{3+}(aq) + NO(g) + 2H_{2}O(l) (acidic)

(b)   The given reaction equation is as follows.

        HCO^{-}_{3}(aq) + Ag(s) + NH_{3}(aq) \rightarrow H_{2}CO(aq) + Ag(NH_{3})^{+}_{2}(aq) (basic)

So, here the reduction and oxidation-half reactions will be as follows.

Reduction-half reaction: HCO^{-}_{3}(aq) + 4e^{-} \rightarrow H_{2}CO(aq)

Oxidation-half reaction: Ag(s) \rightarrow Ag(NH_{3})^{+}_{2}(aq) + 1e^{-}

Hence, to balance the number of electrons in this equation we multiply it by 4 as follows.

      4Ag(s) \rightarrow 4Ag(NH_{3})^{+}_{2}(aq) + 4e^{-}

Therefore, balancing the whole reaction equation in the basic medium as follows.

      H_{2}CO(aq) + 4Ag(NH_{3})^{+}_{2}(aq) + 5OH^{-}(aq) \rightarrow HCO^{-}_{3}(aq) + 4Ag(s) + 8NH_{3}(aq) + 3H_{2}O(l)

6 0
3 years ago
What scientific knowledge was necessary for Kroto, Smalley, and Curl to discover buckyballs? Check all that apply. All matter is
taurus [48]

All matter is made of atoms.

Atoms bond together in certain ways.

Carbon atoms have a specific mass.

8 0
4 years ago
Read 2 more answers
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