The Answer is B. Isotopes
D. How high do the sound waves go
The answer is 20. Frequency is "number of times" per unit time.
Answer:
Length of the string = 0.24 m
Explanation:
The frequency (f) of vibration of stringed instruments is related to the Tension (T) in the spring by the relation
fₙ = (n/2L)√(T/μ)
where n = 1,2,3,4...
For third harmonic frequency, n = 3
L = length of the string = ?
T = tension in the string = 2.3 N
μ = linear density = 4.6 × 10⁻³ kg/m
f = frequency = 140 Hz
L = (n/2f)√(T/μ)
L = (3/(2×140))√(2.3/0.0046) = 0.40 m
Answer:
1110 N
Explanation:
First, find the acceleration.
Given:
Δx = 300 m
v₀ = 85.5 km/h = 23.75 m/s
v = 0 m/s
Find: a
v² = v₀² + 2aΔx
(0 m/s)² = (23.75 m/s)² + 2a (300 m)
a = -0.94 m/s²
Find the force:
F = ma
F = (1180 kg) (-0.94 m/s²)
F = -1110 N
The magnitude of the force is 1110 N.
