Answer:
mount of wire used=12.808989 Km
Amount of wire used=12808.989 m
Explanation:
Given Data:
Diameter of wire=d=0.080 mm=0.00008 m
Weight of wire per unit length=44.5 g/km
Spool weighs=M=570 g
Required:
Amount of wire used=L=?
Solution:
Formula is:
The above expression is mathematical model of finding how much wire is used. just put the Value of M we will get the answer.
Amount of wire used=12.808989 Km
Amount of wire used=12808.989 m
Answer:
4 Ohms
Explanation
(This is seriously not as hard as it looks :)
You only need two types of calculations:
- replace two resistances, say, R1 and R2, connected in a series by a single one R. In this case the new R is a sum of the two:
- replace two resistances that are connected in parallel. In that case:
I am attaching a drawing showing the process of stepwise replacement of two resistances at a time (am using rectangles to represent a resistance). The left-most image shows the starting point, just a little bit "warped" to see it better. The two resistances (6 Ohm next to each other) are in parallel and are replaced by a single resistance (3 Ohm, see formula above) in the top middle image. Next, the two resistances (9 and 3 Ohm) are nicely in series, so they can be replaced by their sum, which is what happened going to the top right image. Finally we have two resistances in parallel and they can be replaced by a single, final, resistance as shown in the bottom right image. That (4 Ohms) is the <em>equivalent resistance</em> of the original circuit.
Using these two transformations you will be able to solve step by step any problem like this, no matter how complex.
The forces of gravity between two objects depend on the masses
of both objects. So if one mass increases, then the objects will be
drawn together by stronger gravitational force.
Example:
When a person eats a lot of steak and fat and carbohydrates, his
mass increases, and the bathroom scale shows that the gravitational
forces drawing him and the Earth together have increased. We say
that he has "gained weight".
i do not know but stop asking qoas
is the charge
<u>Explanation:</u>
The electric fields can be defined as the ratio of electric forces per unit charge.
---------> eq 1
The electric field differs from many quantities such as mass, forces, and speed. The electric field is not a property of a particular object, but a property of a given point in space. All electric charges form an electric field and we can analyse the value (size and direction) of this field at any point in space around the distribution of the charge.
The simplest formula for an electric field is that produced by a point charge:
------> eq. 2
Where,
q - Charge
r - Distance of separation from the charge
k = the Coulomb constant ( )
If the charge is negative, the field is radially inward; if the charge is positive, it is directed radially outward.
Here, given data:
r = 83.9 m
E = 46 N/C
We need to find q.
Substitute the given values in eq 2, we get