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3241004551 [841]
2 years ago
8

Pamela and Debbie are shelving books at a public library. Pamela shelves 26 books at a time, whereas Debbie shelves 7 at a time.

If they end up shelving the same number of books, what is the smallest number of books each could have shelved?
Mathematics
1 answer:
Ira Lisetskai [31]2 years ago
8 0

If both Pamela and Debbie can shelf the same number of books at the end, the smallest number of books each could have shelved is 182

The number of books that Pamela can shelf at a time = 26

The number of books that Debbie can shelf at a time = 7

If both Pamela and Debbie can shelf the same number of books at the end, the smallest number of books each could have shelved is the least common multiple of 26 and 7

The Least common multiple of 26 and 7  = 182

Therefore, if both Pamela and Debbie can shelf the same number of books at the end, the smallest number of books each could have shelved is 182

Learn more on Least Common Multiple here: brainly.com/question/363238

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On monday it took 5 builders to 3 1/2 hours to build a wall
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Step-by-step explanation:

Given: On Monday,

5 builders took 3\dfrac{1}{2} hours  ( i.e. \dfrac{7}{2} hours )  to build a wall.

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As workers are inversely proportional to the time if the job remains constant.

Inverse variation equation : x_1y_1=x_2y_2

Let x be the time taken by 2 builders, then

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