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Rom4ik [11]
3 years ago
13

Cups are sold 6 to a package and plates are sold 8 to a package. If you want to have the same number of each item for a party

Mathematics
1 answer:
beks73 [17]3 years ago
3 0

Answer:

24

Step-by-step explanation:

If you want to find the least amount of packages, you'll have to find what multiple they have in common.

One way to find this is 6x8, which is 48, but that isn't always the lowest.  

Here are the first few multiples of six: 6, 12, 18, (24), 30, 36, 42, and 48.

Here are the first few multiples of eight: 8, 16, (24), 32, 40, 48, 56, and64

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What is the area of the parallelogram
Airida [17]

Answer:

  24 square units

Step-by-step explanation:

For such questions it is convenient to choose the "base" to be a segment that is aligned with one of the coordinate axes. Here, the horizontal segments will serve. Their length is the difference between the x-coordinates of the end points, -2 -(-6) = 4, for example.

The height is measured perpendicular to the base, so will be the difference between the y-coordinates of the horizontal segments: 2 -(-4) = 6.

The area is given by the formula ...

  A = bh

  A = 4·6 = 24 . . . square units

3 0
2 years ago
MIDPOINT & DISTANCE help
tamaranim1 [39]

Answer:

<h2>M(-6, 4)</h2>

Step-by-step explanation:

The formula of a midpoint of (x₁, y₁) and (x₂, y₂):

M\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)

We have two points (-3, 7) and (-9, 1).

Substitute:

x=\dfrac{-3+(-9)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{7+1}{2}=\dfrac{8}{2}=4

5 0
3 years ago
What Is the Intersection of Two Sets
denis-greek [22]

Answer:

the set of elements that are common to each of the given sets

Step-by-step explanation:

8 0
2 years ago
What does the expression n+3 represent?
Sati [7]
Do you know what n equals so i can solve it?<span />
5 0
3 years ago
1. A weighted coin is biased so that a head is twice as likely to occur as a tail. If the coin is tossed 4 times, what is the pr
ohaa [14]

Answer:

80/81

Step-by-step explanation:

If a head is twice as likely to occur as a tail, then the probability of getting heads is 2/3 and the probability of getting tails is 1/3.

The probability of getting at least 1 head involves 4 scenarios:

1) 1 Head and 3 Tails

2) 2 Heads and 2 Tails

3) 3 Heads and 1 Tail

4) 4 Heads

Instead of calculate all these scenarios, you could calculate the opposite scenario: 4 Tails. The sum of all possible scenarios is 1, so:

P(at least one head) + P(no heads) = 1

Then, P(at least one head) = 1 - P(no heads)

The probability of 4 tails is:

P(no heads) = P(TTTT) = (1/3)(1/3)(1/3)(1/3)=1/81

Then, P(at least one head) = 1 - 1/81=80/81

7 0
3 years ago
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