Answer:
3.91 N/C
Explanation:
u = 0, s = 5.50 m, t = 4 us = 4 x 10^-6 s
Let a be the acceleration.
Use second equation of motion
s = u t + 1/2 a t^2
5.5 = 0 + 1/2 a (4 x 10^-6)^2
a = 6.875 x 10^11 m/s^2
F = m a
The electrostatic force, Fe = q E
Where E be the strength of electric field.
So, q E = m a
E = m a / q
E = (9.1 x 10^-31 x 6.875 x 10^11) / ( 1.6 x 10^-19)
E = 3.91 N/C
Answer:
P car = 1500×400/12= 50,000kgm/s
P electron= 9.1×3.5×10^(-31+6)
= 31.85×10^-25 kgm/s
Explanation:
work done =force *distance
work done =17000*26
work done=442,000 joules.