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3 years ago

Examples of microhabitats could be a rotting tree stump or a dead animal. List 3 microhabitats.

Chemistry

2 answers:

jenyasd209 [6]3 years ago

8 0

Answer:

Examples of microhabitats on the short grass prairie of the Llano Estacado include temporary pools of water, a decomposing log or animal, cryptobiotic soils, lichen growth, under rocks, leaf litter, termite tubes, and the interior of an ant bed.

There are different types of microhabitats in a wood, namely, coniferous forest, open woodland, broad-leafed forest, clearings and glades, smooth barks, rotten wood, damaged barks, canopy, and shrub layer, among many other variations.

Grace [21]3 years ago

3 0

Answer: Okay!

Explanation: Well then the third thing could be dead plant? You already have 2 other things

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If a refrigerator is a heat pump that follows the first law of thermodynamics, how much heat was removed from food inside of the

kirill115 [55]

The first law of thermodynamics states the conservation of energy and heat where the total energy in an isolated system may be transformed into another, but never created or destroyed. If 314 J of energy was released to the room, then also 314 J of energy was also removed from food in that refrigerator assuming it is an isolated system.

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3 years ago

Which must be the same when comparing 1 mol of oxygen gas, O2, with 1 mol of carbon

babymother [125]

C the number of molecules

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3 years ago

Read 2 more answers

Calculate the enthalpy change, ΔH, for the process in which 30.1 g of water is converted from liquid at 10.1 ∘C to vapor at 25.0

gayaneshka [121]

You can split the process in two parts:

1) heating the liquid water from 10.1 °C to 25.0 °C , and

2) vaporization of liquid water at constant temperature of 25.0 °C.

For the first part, you use the formula ΔH = m*Cs*ΔT

ΔH = 30.1g * 4.18 j/(g°C)*(25.0°C - 10.1°C) = 1,874 J

For the second part, you use the formula ΔH = n*ΔHvap

Where n is the number of moles, which is calculated using the mass and the molar mass of the water:

n = mass / [molar mass] = 30.1 g / 18.0 g/mol = 1.67 mol

=> ΔH = 1.67 mol * 44,000 J / mol = 73,480 J

3) The enthalpy change of the process is the sum of both changes:

ΔH total = 1,874 J + 73,480 J = 75,354 J

Answer: 75,354 J

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3 years ago

What are the various ways in which an atom of an element can achieve the noble gas configuration ?

azamat

Answer:

<h3>Atoms attain noble gas configuration by obtaining or donating and sharing of electrons present in their outermost shell. </h3>

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3 years ago

A compound with molecular formula C6H15N exhibits a singlet at d 0.9 (1H), a triplet at d 1.10 (3H), a singlet at d1.15 (9H), an

LuckyWell [14K]

Answer:

N-ethyl-2-methylpropan-2-amine

Explanation:

In this case, we have to start with the IR info. The signal on 3400 cm^-1 indicates the presence of a hydrogen bonded to the heteroatom. In this case, we have nitrogen in the formula, so we will have the amine group.

On the other hand, we have to analyze the NMR info:

a) We have 2 singlets => This indicates the presence of 2 different hydrogens without neighbors.

b) We have a triplet => This indicates the presence of CH3 bonded to a CH2.

c) We have a quartet => This indicates the presence of CH2 bonded to a CH3.

From b) and c) we can conclude that we have the ethyl group bonded to a nitrogen.

Finally, we have to add 4 more carbons in such a way that we only have a single signal. In this case the ter-butyl group.

In that way, we will have 2 singlets (from the CH3 groups in the ter-butyl and the H on the N). Also, we will have the quartet on the CH2 in the ethyl group and the triplet on the CH3 in the ethyl group

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3 years ago