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3 years ago

(363 × 1.48)/3.5-1.79 + 6.1 × 10^−1

1 answer:

8 0

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(363)(1.48)
3.5
−1.79+6.1(10−1)=152.317143

(363×1.48)/3.5-1.79+6.1×10^-1
CALCULATE IT!
Simplify
Step-By-Step

(363)(1.48)
3.5
−1.79+6.1(10−1)
=
537.24
3.5
−1.79+6.1(10−1)
=153.497143−1.79+6.1(10−1)
=151.707143+6.1(10−1)
=151.707143+6.1(
1
10
)
=151.707143+0.61
=152.317143

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If -3(x + 6) = x - 2, then x = -4.

Anon25 [30]

3(x + 6) = x - 2

3(-4+6)= -4-2

mutiply the bracket by 3

(3)(-4)= -12

(3)(6)= 18

-12+18= -4-2

6= -4-2

6= -6

Answer:

No solution

4 0

2 years ago

What is the sum of 4/10 + 55/100

neonofarm [45]

4/10 = 40/100

40/100 + 55/100 = 95/100

95/100 is your answer

simplest form: 19/20

hope this helps

4 0

2 years ago

Read 2 more answers

Help plz no wrong answers plz help me ASAP thanks!

wariber [46]

Answer:

480

Step-by-step explanation:

The probability she will roll 2 odd numbers is 12/50 (the number of odd rolls over the total). This simplifies to 6/25

Multiply the probability times the total number of rolls to get a good estimate of the number of rolls that till be odd odd

6/25 * 2000 =480

5 0

3 years ago

A simple die is thrown 100 times and the number five appears 14 times. Find the experimental probability of throwing a five, giv

mario62 [17]

Answer:

The experimental probability of throwing a five is 0.087.

Step-by-step explanation:

Given:

Number of trials (n) = 100

Number of times 5 appears (x) = 14

Let the event of occurrence of 5 be success and the probability represented by 'p'. So, all the other numbers occurrence is failure and its probability is represented as 'q'.

Probability of success is given as:

$p=\frac{Number\ of\ favorable\ events}{Total\ number\ of\ outcomes}$

Favorable event is occurrence of 5. So, its number is 1 as there is only one 5 in the die. Total outcomes are 6 as there are six numbers. So,

$p=\frac{1}{6}$

Now, probability of failure is given by the formula:

$q=1-p=1-\frac{1}{6}=\frac{5}{6}$

Now in order to find the experimental probability of 14 successes out of 100 trials, we apply Bernoulli's theorem which is given as:

$P(x) = ^nC_xp^xq^{n-x}$

Plug in all the given values and find the probability of 14 successes. This gives,

$P(x=14)=^{100}C_{14}(\frac{1}{6})^{14}(\frac{5}{6})^{100-14}\\\\P(x=14)=0.087$

Therefore, the experimental probability of throwing a five is 0.087.

8 0

3 years ago

Jason is tossing a fair coin. He tosses the coin ten times and it lands on heads eight times. If Jason tosses the coin an eleven

nikdorinn [45]

:Jason is tossing a fair coin. He tosses the coin ten times and it lands on heads eight times. If Jason tosses the coin an eleventh time, what is the probability that it will land on heads?
Solution:

The probability would be ½. The result of the eleventh toss does not depend on the previous
results.

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3 years ago