Answer:
4
Step-by-step explanation:
Volume= length*width*height
72=Length*3*6
72=Length*18
divide by 18 both sides to get Length=4 inches
<h2><u>Direct answer</u> :</h2><h2>
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</h2>
- Segment AO = Segment KT
- Segment OR = Segment TE
- ∠AOR = ∠KTE
- △AOR≅△KTE
<h2 /><h2>
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</h2>
- It is given.
- It is given.
- It is given.
- Since two sides and one incised angle is equal in both the triangles we can conclude that they are congruent under the SAS congruence criterion.
<h3>Steps to derive these statements and resons :</h3>
Given :
In triangle AOR and triangle KTE :
- Segment AO = Segment KT
- Segment OR = Segment TE
- ∠AOR = ∠KTE
Since two sides and one included angle of these two triangles are equal, we can conclude that these triangles are congruent under the SAS congruence criterion.
I’m working on it right now, so give me some time please
Hey there!
In order to find out which one is greater, lets convert both of them into percents.
To convert a decimal into a percent, simply multiply the decimal by 100 or move the decimal two places to the right.
So!
0.086 × 100 = 8.6%
Now, we know that 0.086 is equal to 8.6% So, the correct answer is 86%
86% is greater than 0.086.
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Answer:
It is likely that the birth weight of a random baby boy will be between 3.2 and 3.4 kg because the probability of this event is large enough.
Step-by-step explanation:
Population mean=μ=3.3.
S.E=0.1.
n=36.
If the probability of the birth weight of a random baby boy will be between 3.2 and 3.4 kg is larger than the it will be likely. The probability can be calculated by normal distribution because sample size is large enough.
Z-score for 3.2 kg=3.2-3.3/0.1=-1
Z-score for 3.4 kg=3.4-3.3/0.1=1
P(-1<Z<1)=P(-1<Z<0)+P(0<Z<1)
P(-1<Z<1)=0.3413+0.3413
P(-1<Z<1)=0.6826
The probability of the birth weight of a random baby boy will be between 3.2 and 3.4 kg is 68.26%. So. it is likely that the birth weight of a random baby boy will be between 3.2 and 3.4 kg as the probability is large enough.