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2 years ago

(Will be giving brainliest)

Mathematics

1 answer:

REY [17]2 years ago

7 0

Answer:

u totally need to put an image or else no one is gonna be able to answer it.

Step-by-step explanation:

by the way the answers are randomly generated by it seems like the answers are always B or C

Answer is likely B or C

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PLEase Help ME In This Work!!

tigry1 [53]

Answer:

y=2x

Step-by-step explanation:

it is a proportional relationship and the slope is 2

8 0

3 years ago

Subtract the following complex numbers:<br> (3 +31) - (13+15)

vova2212 [387]

Answer:

33-28=5

Step-by-step explanation:

hope this helps

6 0

3 years ago

Read 2 more answers

What is the median number of 4,8,10,5,9

Nady [450]

The answer is 10. because median means middle so 10 is the middle #.

5 0

3 years ago

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Enter the value for x that makes the equation 1/2 (4x+12)+5x=30 true.

8090 [49]

First, distribute the (1/2) into (4x+12) by multiplying them.

The equation becomes:

2x + 6 + 5x = 30

On the left side, combine “like terms” through addition.

7x + 6 = 30

Subtract 6 from both sides:

7x = 24

Finally, get x alone by dividing both sides by 7:

x = 24/7, or if you wanted to round the decimal answer, it’s about 3.429.

8 0

3 years ago

Prove the divisibility of the following numbers:

Brut [27]

Answer:

Step-by-step explanation:

To prove divisibility, we need to factor the divident such that one of its factors matches the divisor.

(I use the notation x|y to denote that x divides y)

(A)

$75^{30}|45^{45}\cdot15^{15}\\45^{45}\cdot15^{15}=3^{45}\cdot 15^{45}\cdot 15^{15}=\\=3^{45}\cdot 15^{60}=3^{45}\cdot 15^{30}\cdot 15^{30}=3^{45}\cdot (3\cdot5)^{30}\cdot 15^{30}=\\=3^{45}\cdot 3^{30}\cdot(5\cdot 15)^{30}=3^{45}\cdot 3^{30}\cdot(75)^{30}\\\implies\\75^{30}|3^{45}\cdot 3^{30}\cdot75^{30}$

(B)

$72^{63}|24^{54}\cdot 54^{24}\cdot2^{10}\\24^{54}\cdot 54^{24}\cdot2^{10}=(2^{162}\cdot 3^{54})\cdot(2^{24}\cdot 3^{72}) \cdot 2^{10}\\=2^{196}\cdot 3^{126}$

In this case, it is easier to also factor the divisor to primes:

$72^{63}=2^{189}\cdot 3^{126}$

Both of these factor must be matched in the dividend in order to prove divisibility, and that indeed turns out to be true:

$2^{189}\cdot 3^{126}|2^{196}\cdot 3^{126}\implies\\2^{189}|2^{196}\,\,\mbox{and}\,\,3^{126}|3^{126}$

6 0

3 years ago