Answer:
Explanation:
Hello!
In this case, according to the following chemical reaction:
It means that we need to compute the moles of hydrogen and oxygen that are reacting, via the ideal gas equation as we know the volume, pressure and temperature:
Thus, the yielded moles of water are computed by firstly identifying the limiting reactant:
Thus, the fewest moles of water are 0.0609 mol so the limiting reactant is oxygen; in such a way, by using the ideal gas equation once again, we compute the pressure of water:
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Answer:
The value of 
for this reaction at 1200 K is 4.066.
Explanation:
Partial pressure of water vapor at equilibrium = 
Partial pressure of hydrogen gas at equilibrium = 
Total pressure of the system at equilibrium P = 36.3 Torr
Applying Dalton's law of partial pressure to determine the partial pressure of hydrogen gas at equilibrium:
The expression of is given by:
The value of for this reaction at 1200 K is 4.066.
The true statement about the balanced equations for nuclear and chemical changes is; both are balanced according to the total mass before and after the change.
A basic law in science is called the law of conservation of mass. Its general statement is that mass can neither be created nor destroyed.
Both in chemical and nuclear changes, mass is involved and in both cases, the law of conservation of mass strictly applies.
This means that for both chemical and nuclear changes; total mass before reaction must be equal to total mass after reaction.
Hence, both reactions are balanced according to the total mass before and after the change.
Learn more: brainly.com/question/22064431
Answer:
Molecules are made up of atoms and are the smallest parts of compounds that still have properties. Atoms are the smallest parts of elements that still have properties.
Explanation:
We can set up an ICE table for the reaction:
HClO H+ ClO-
Initial 0.0375 0 0
Change -x +x +x
Equilibrium 0.0375-x x x
We calculate [H+] from Ka:
Ka = 3.0x10^-8 = [H+][ClO-]/[HClO] = (x)(x)/(0.0375-x)
Approximating that x is negligible compared to 0.0375 simplifies the equation to
3.0x10^-8 = (x)(x)/0.0375
3.0x10^-8 = x2/0.0375
x2 = (3.0x10^-8)(0.0375) = 1.125x10^-9
x = sqrt(1.125x10^-9) = 0.0000335 = 3.35x10^-5 = [H+]
in which 0.0000335 is indeed negligible compared to 0.0375.
We can now calculate pH:
pH = -log [H+] = - log (3.35 x 10^-5) = 4.47
