Answer:
The answer is
<h2>8.89 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula

From the question
mass of copper = 24 g
volume = 2.7 mL
The density of the metal is

We have the final answer as
<h3>8.89 g/mL</h3>
Hope this helps you
Answer:
The mass of iron produced is 44.29 grams
Explanation:
Al + FeO3
Aluminium + Iron III oxide
2Al + F₂O₃ → Al₂O₃ + 2Fe
Molar mass of Al = 26.981539 g/mol
Molar mass of F₂O₃ = 159.69 g/mol
Number of moles of Aluminium = 21.4 g/26.981539 g/mol = 0.7931 moles
Number of moles of F₂O₃ = 91.3 g/159.69 g/mol = 0.572 moles
Hence, 1 mole of Al combines with 1/2 moles of F₂O₃, 0.7931 moles of Al will combine with 0.7931 × 1/2 or 0.3966 moles of F₂O₃ to produce 0.7931 moles of iron
Molar mass of iron = 55.845 g/mol
Therefore the mass of iron produced = Number of moles × Molar mass = 0.7931 × 55.845 = 44.29 grams.
Answer:
First, precipitate of AgCl is formed. Second, a soluble complex of silver and ammonia is formed. Third, AgCl is reproduced due to disappearance of ammonia complex in presence of
.
Explanation:
In presence of NaCl,
forms an insoluble precipitate of AgCl.
Reaction: 
In presence of
, AgCl gets dissolved into solution due to formation of soluble
complex.
Reaction: ![AgCl(s)+2NH_{3}(aq.)\rightarrow [Ag(NH_{3})_{2}]^{+}(aq.)+ Cl^{-}(aq.)](https://tex.z-dn.net/?f=AgCl%28s%29%2B2NH_%7B3%7D%28aq.%29%5Crightarrow%20%5BAg%28NH_%7B3%7D%29_%7B2%7D%5D%5E%7B%2B%7D%28aq.%29%2B%20Cl%5E%7B-%7D%28aq.%29)
In presence of
,
complex gets destroyed and free
again reacts with free
to produce insoluble AgCl
Reaction: ![[Ag(NH_{3})_{2}]^{+}(aq.)+2H^{+}(aq.)+Cl^{-}(aq.)\rightarrow AgCl(s)+2NH_{4}^{+}(aq.)](https://tex.z-dn.net/?f=%5BAg%28NH_%7B3%7D%29_%7B2%7D%5D%5E%7B%2B%7D%28aq.%29%2B2H%5E%7B%2B%7D%28aq.%29%2BCl%5E%7B-%7D%28aq.%29%5Crightarrow%20AgCl%28s%29%2B2NH_%7B4%7D%5E%7B%2B%7D%28aq.%29)