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patriot [66]
3 years ago
6

the temperature of a smelting furnace is found to be 2000 degree celsius. find the equivalent temperature on (a) the fahrenheit

scale (b) the Rankine scale (c) the absolute scale (d) Reaumer scale ​
Physics
2 answers:
Rus_ich [418]3 years ago
6 0

Answer:

(a) F = (9/5 * C) + 32

put the 2000 in C and find the value

(b) R = F + 459.67

substitute value of F to get R

(c) Absolute scale = C + 273.15

(d) Re = C * 0.8

hope it helps

emmasim [6.3K]3 years ago
5 0

Answer:

I'd don't know about this sorry

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Atoms of most elements are less likely to react when they have
sergejj [24]

Answer:

when they have 8 valence electrons

8 0
3 years ago
An iron wire has a cross-sectional area equal to 5.00×10⁻⁶ m² . Carry out the following steps to determine the drift speed of th
Doss [256]
  1. In mass, there are 55.85 × 10⁻³ kg/mol in in 1 mole of iron.
  2. The molar density of iron is equal to 1.41 × 10⁵ mol/m³.
  3. The density of iron atoms is equal to 8.49 × 10²⁸ atoms/m³.
  4. The number density of conduction electrons is equal to 1.70 × 10²⁹ conduction electrons/m³.
  5. The drift speed of conduction electrons is equal to 2.21 × 10⁻⁴ m/s.

<h3>How to calculate the drift speed of the conduction electrons?</h3>

Mathematically, the drift speed of the conduction electrons can be calculated by using this formula:

V = (m × σ × V)/ρ × e × f × l)

V = I/(n × A × Q)

Where:

  • U represents the drift speed of the conduction electrons, in m/s.
  • m represents the molecular mass of the metal, in kg.
  • e represents the elementary charge, in C.
  • f represents the number of free electrons per atom.
  • σ represents the electric conductivity of the medium at a particular temperature in S/m.
  • ρ represents the density of the conductor, in kg/m³.
  • ℓ represents the length of the conductor, in m.
  • ΔV represents the voltage applied or potential difference across the conductor in V.

<h3>How many kilograms are there in 1 mole of iron? </h3>

Molar mass of iron = 55.85 g/mol.

In Kilograms, we have:

Mass = 55.85 × 1/1000

Mass = 55.85 × 10⁻³ kg/mol.

For the molar density of iron, we have:

Molar density = density/molar mass

Molar density = 7874/0.056

Molar density = 1.41 × 10⁵ mol/m³.

For the density of iron atoms, we have:

Density of iron atoms = Avogadro's constant × molar density

Density of iron atoms = 6.023 × 10²³ × 1.406 × 10⁵

Density of iron atoms = 8.49 × 10²⁸ atoms/m³.

For the number density of conduction electrons, we have:

Fe ---> Fe²⁺ + 2e⁻

Number density of conduction electrons = 2 conduction electrons/1 atom of iron

Number density of conduction electrons = 2 × 8.49 × 10²⁸

Number density of conduction electrons = 1.70 × 10²⁹ conduction electrons/m³.

For the drift speed of conduction electrons, we have:

V = I/(n × A × Q)

V = 30/(1.70 × 10²⁹ × 1.602 × 10⁻¹⁹ × 5 × 10⁻⁶)

Drift speed, V = 2.21 × 10⁻⁴ m/s.

Read more on drift speed here: brainly.com/question/15219891

#SPJ4

Complete Question:

An iron wire has a cross-sectional area of 5.00 x 10-6 m2. Carry out steps (a) through (e) to compute the drift speed of the conduction electrons in the wire.

(a) How many kilograms are there in 1 mole of iron?

(b) Starting with the density of iron and the result of part (a), compute the molar density of iron (the number of moles of iron per cubic meter).

(c) Calculate the number density of iron atoms using Avogadro’s number.

(d) Obtain the number density of conduction electrons given that there are two conduction electrons per iron atom.

(e) If the wire carries a current of 30.0 A, calculate the drift speed of conduction electrons.

4 0
2 years ago
The equation for a travelling wave is y = 4.6 Sin (3t-8x) Find: (a) Its frequency (b) Its wave length (c) Speed of the wave.​
Kaylis [27]

Explanation:

Explanation:

Y = 5 Sin27(.2x-3t)

= 5 Sin(5.4x - 81 t)

Amplitude = 5 m

Angular frequency w = 81

frequency = w/ 2π = 81/(2 x 3.14)

-12.89

Wave length λ = 2π/ k,

k = 5.4

λ = 2π/ 5.4

= 1.163 m

Phase velocity=w / k

= 81/5.4

15 m/s.

The wave is travelling in + ve x - direction.

hope help

6 0
3 years ago
A 100kg diver jumps off a 40m cliff. Ignoring the affects of air resistance, determine the
sashaice [31]

Answer:2.86seconds

Explanation:

H=gt^2/2

t=2h/g

6 0
3 years ago
Consider two identical electric bulbs of power P and resistance R. You connect them to a battery of voltage V. The first time yo
natulia [17]

Answer:

The answer is 2X as much illumination as connection in series

Explanation:

We are given from the question that the two bulbs are identical in power and resistance.

Firstly we know that In a series connection the Voltage across the circuit elements are different whereas In a parallel connection, the same value of voltage passes through all the circuit elements.

Power is expressed as ;

P = V^2/ R

An increase in voltage leads to an increase in power likewise if the voltage is reduced the power also reduces.

The two bulbs are said to be having the same resistances , so the voltage across them in a series connection will be halved

V =1/2V1 + 1/2 V2; making the illumination across them to be low.

Therefore in parallel the illumination will be twice as much the illumination when connected in series.

4 0
4 years ago
Read 2 more answers
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