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Verizon [17]
3 years ago
10

Which equation represents a linear function??

Mathematics
1 answer:
GarryVolchara [31]3 years ago
8 0

Answer:

the linear function is y=-3^2+1

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HELP ME SOLVE THIS PROBLEM PLEASE! :)
lukranit [14]
The answer would be the first option :
4/3r (3x)^3.

Hope this helps !

Photon
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4 years ago
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Find the average rate of change of the function over the given interval
sattari [20]
\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\

\bf h(t)=cot(t)\implies h(t)=\cfrac{cos(t)}{sin(t)}\quad 
\begin{cases}
t_1=\frac{\pi }{4}\\
t_2=\frac{3\pi }{4}
\end{cases}\implies \cfrac{h\left( \frac{3\pi }{4} \right)-h\left( \frac{\pi }{4} \right)}{\frac{3\pi }{4}-\frac{\pi }{4}}
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\bf \cfrac{\frac{cos\left( \frac{3\pi }{4} \right)}{sin\left( \frac{3\pi }{4} \right)}-\frac{cos\left( \frac{\pi }{4} \right)}{sin\left( \frac{\pi }{4} \right)}}{\frac{\pi }{2}}\implies \cfrac{-1-1}{\frac{\pi }{2}}\implies \cfrac{-2}{\frac{\pi }{2}}\implies -\cfrac{4}{\pi }\\\\\\
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\bf h(t)=cot(t)\implies h(t)=\cfrac{cos(t)}{sin(t)}\quad 
\begin{cases}
t_1=\frac{\pi }{3}\\
t_2=\frac{3\pi }{2}
\end{cases}\implies \cfrac{h\left( \frac{3\pi }{2} \right)-h\left( \frac{\pi }{3} \right)}{\frac{3\pi }{2}-\frac{\pi }{3}}
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\bf \cfrac{\frac{cos\left( \frac{3\pi }{2} \right)}{sin\left( \frac{3\pi }{2} \right)}-\frac{cos\left( \frac{\pi }{3} \right)}{sin\left( \frac{\pi }{3} \right)}}{\frac{9\pi -2\pi  }{6}}\implies \cfrac{\frac{0}{-1}-\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}}{\frac{7\pi }{6}}\implies\cfrac{-\frac{1}{\sqrt{3}}}{\frac{7\pi }{6}}\implies -\cfrac{\sqrt{3}}{3}\cdot \cfrac{6}{7\pi }
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-\cfrac{2\sqrt{3}}{7\pi }
8 0
4 years ago
HELP ON THIS PLS MATH
Artemon [7]

Answer:

7

Step-by-step explanation:

1 hour = 118 guests

826 / 118 = 7 hours

6 0
3 years ago
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Factor 16p4 - 24p3. find the factor
Stolb23 [73]

Answer:

8p^3 ( 2p -3)

Step-by-step explanation:

16p^4 - 24p^3

8*2* p^3 *p - 3*8*p^3

Factor out the common terms

8p^3 ( 2p -3)

5 0
3 years ago
Find the length of the arc on a circle with a radius of 2.4 kilometers and is intercepted by a central angle measuring 150°. lea
Kaylis [27]

If the radius of the circle exists 2.4 kilometers and is intercepted by a central angle measuring 150° then the length of the arc exists 5π inches.

<h3>What was the relation between the central angle and its intercepted arc?</h3>
  • If the vertex of an angle exists in the center of the circle and the two sides of the angle are radii in the circle, then this angle exists named a central angle.
  • Each central angle exists subtended by the opposite arc, the name of the arc exists the starting point and the finish point of the angle.
  • There exists a relation between the central angle and its subtended arc the measure of the central angle equals half the measure of its subtended arc.
  • The length of the subtended arc relies on the measurement of its central angle and the length of the radius and the measure of the arc.
  • The measurement of the circle exists at 360°.
  • The length of the circle exists at 2πr.

The radius of the circle r = 2.4 kilometers

The measure of the central angle exists at 150°.

The length of the arc = central angle/360 × 2πr

The length of the arc = 150°/360° × 2 × π × 2.4 = 2π

The length of the arc exists 2π kilometers.

To learn more about arc length refer to:

brainly.com/question/11134371

#SPJ4

4 0
2 years ago
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