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2 years ago

7

Theorem: A line parallel to one side of a triangle divides the other two proportionately.

2 answers:

guapka [62]2 years ago

6 0

Answer: Segment BF = 16

Step-by-step explanation:

meriva2 years ago

5 0

Answer: Segment BD = 15

Step-by-step explanation: Ok. So, we know that segment DE is parallel to segment BC and segment EF is parallel to segment AB. The triangle proportionality theorem states that if a line is parallel to one side of a triangle and also intersects the other two sides, the line divides the sides proportionally. To put it more simply; because segment EF is parallel to segment AB, triangles ADE and EFC are proportional and similar. From there we must find the scale factor by which these two triangles are proportional.

We can do this by dividing the corresponding segments by; each other.

24 ÷ 20 = 1.2

Scale Factor = 1.2

Then we divide segment AD (18) by the scale factor (1.2).

18 ÷ 1.2 = 15

Since segment EF is parallel to segment AB, segment EF corresponds and is congruent to segment DB.

So,

Segment BD = 15

I also got it right on the test, soooo.... yeah

Thar ya go

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Liono4ka [1.6K]

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A right rectangular prism is packed with cubes of side length fraction 1 over 5 inch. If the prism is packed with 15 cubes along

Ann [662]

Given:

A right rectangular prism is packed with cubes of side length $\dfrac{1}{5}$ inch.

Prism is packed with 15 cubes along the length, 6 cubes along the width, and 5 cubes along the height.

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The volume of the prism

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Side length of each cube $=\dfrac{1}{5}$ inch.

15 cubes along the length, so length of prism is

$l=15\times \dfrac{1}{5}=3\text{ inches}$

6 cubes along the width, so width of prism is

$b=6\times \dfrac{1}{5}=\dfrac{6}{5}\text{ inches}$

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$h=5\times \dfrac{1}{5}=1\text{ inch}$

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