If you divide 68.5 km/h by 60 (the minutes in an hour) and then you get 1.141 then you multiply it by 5.45 and you get 6.222!
Your Answer is 6.222!!!!
Answer:
Part 1
20 N
Part 2
0.4 m/s²
Part 3
4 m/s
Explanation:
The force which pulls the sled right = 50 N
The friction force exterted towards left by the snow = -30 N
The mass of the sled = 50 kg
Part 1
The sum of the forces on the sled, F = 50 N + (-30) N = 20 N
Part 2
The acceleration of the sled is given as follows;
F = m·a
Where;
m = The mass of the sled
a = The accelertion
a = F/m
∴ a = (20 N)/(50 kg) = 0.4 m/s²
The acceleration of the sled, a = 0.4 m/s²
Part 3
The initial velocity of the sled, u = 2 m/s
The kinematic equation of motion to determine the speed of the sled is v = u + a·t
The speed, <em>v</em>, of the sled after t = 5 seconds is therefore;
v = 2 m/s + 0.4 m/s² × 5 s = 4 m/s.
Answer:
<h2>0.5J</h2>
Explanation:
given data
Force applied F= 1N
extension e= 0.1m
let us find the spring constant first
applying
F=ke
k=F/e
k=1/0.1
k=10N/m
Step two:
Required is the work done
we know that the expression/formula for the work done by a spring is given as
Wd=1/2kx^2
x=0.4m
substitute
Wd= 1/2*10*0.4^2
Wd=0.5*10*0.16
Wd=0.5J
To solve this problem we will apply the concepts related to the kinematic equations of linear motion. We will calculate the initial velocity of the object, and from it, we will calculate the final position. With the considerations made in the statement we will obtain the total height. Initial velocity of the acorn,
Also, it is given that the acorn takes 0.201s to pass the length of the meter stick.
Replacing,
The height of the acorn above the meter stick can be calculated as,
Also the top of the meter stick is 1.87m above the ground hence the height of the acorn above the ground is
