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3 years ago

What are the properties of a thermometer

Physics

1 answer:

lesya [120]3 years ago

3 0

Answer:

The thermometer makes use of a physical property of a thermometric substance which changes continuously with temperature. The physical property is referred to as thermometric property.

...

Thermometric Properties Used In Various Thermometers.

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18) A charm quark has a charge of approximately

Allushta [10]

Based on scientific records, a charm quark has a charge that's approximately equal to: 2) 1.07 × 10⁻¹⁹ C.

<h3>What is a charge?</h3>

A charge simply refers to a fundamental, physical property of matter that governs how the particles of a substance are affected by an electromagnetic field, especially due to the presence of an electrostatic force (F).

Also, charge is typically measured in Coulombs and a charm quark (elementary particle) has a charge that's approximately equal to 1.07 × 10⁻¹⁹ Coulomb.

Read more on charges here: brainly.com/question/4313738

#SPJ1

3 0

2 years ago

10. A 12 kg load hangs from one end of a rope that passes over a small frictionless pulley. A 15 kg counterweight is suspended f

nekit [7.7K]

Answer:

Explanation:

6 0

3 years ago

To test a slide at an amusement park, a block of wood with mass 3.00 kgkg is released at the top of the slide and slides down to

dem82 [27]

Answer:

511.1 J

Explanation:

We are given that

Mass of wood block=m=3 kg

Vertical distance,h=23 m

Horizontal distance =x=30 m

Distance traveled in downward direction y=40 m

Initial velocity,u=0

$y=ut+\frac{1}{2} gt^2$

Where $g=9.8 m/s^2$

$40=0+\frac{1}{2}(9.8)t^2=4.9t^2$

$t^2=\frac{40}{4.9}$

$t=\sqrt{\frac{40}{4.9}}=2.86 s$

$x=v_x\times t$

$30=v_x(2.86)$

$v=v_x=\frac{30}{2.86}=10.49 m/s$

By work energy theorem

Change in kinetic energy=Work done= mgh-W

$\frac{1}{2}mv^2-\frac{1}{2}mu^2=3\times 9.8\times 23-W$

$\frac{1}{2}(3)(10.49)^2-0=676.2-W$

$W=676.2-\frac{1}{2}(3)(10.49)^2=511.1 J$

Hence, the work done due to friction on the block as it slides down the ramp=511.1 J

6 0

3 years ago

A cop claims you passed him at more than 60 mph ,27.8 meters per second, 200 meters from a red light that just turned green. you

postnew [5]

Sounds like the situation is modeled like so:

[Light] - - - - - - - - - - [You] => - - -

- - - - - - - - - - - - - - - [Cop] - - - - -

<= = = 200 m = = =>

where your velocity is 27.8 m/s to the right. So the question is asking, is it possible that your car, given that it accelerates at a maximum of 1/5 m/s^2, can reach a speed of 27.8 m/s from rest in the time it takes for it to cover 200 m.

The car's position at time $t$ is