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Tatiana [17]
2 years ago
13

Selena, who moves with the grace and fluid motions of a cat, has been described as

Physics
1 answer:
MaRussiya [10]2 years ago
6 0
Porcine = of, affecting, or resembling a pig or pigs
Equine = of, relating, or affecting horses or other members of the horse family
Ursine = of, relating to, or resembling bears
Feline = Of, relating to, or affecting cats or other members of the cat family

Your answer is option "D. feline"

(definitions from "New Oxford American Dictionary)


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Two 13 cm -long thin glass rods uniformly charged to +11nC are placed side by side, 4.0 cm apart. What are the electric field st
DedPeter [7]

Answer:

E1  = 10.15 * 10^4 N/C

E2 = 0

E3 = 10.15 *10^4 N/C

Explanation:

Given data:

Two 13 cm-long thin glass rods ( L ) = 0.13 m

charge (Q)  = +11nC

distance between thin glass rods   = 4 cm .

<u>Calculate the electric field strengths </u>

electric charge due to a single glass rod in the question ( E ) = \frac{Q}{2\pi e_{0}rL }

equation 1 can be used to determine E1, E2 and E3 because the points lie within the two rods hence the net electric field produced will be equal to the difference in electric fields produced

applying equation 1 to determine E1

E1 = \frac{Q}{2\pi e_{0}rL } ( \frac{1}{0.01} - \frac{1}{0.03} )    ( distance from 1 rod is 0.01 m and from the other rod is 0.03 )

   = \frac{11*10^{-9} }{2*3.14*8.85*10^{-12}*0.13 } ( 66.67 )

   = 10.15 * 10^4 N/C

applying equation 1 to determine E2

E2 = \frac{Q}{2\pi e_{0}rL }( \frac{1}{0.02} - \frac{1}{0.02} )

therefore E2 = 0

E1 = E3

hence E3 = 10.15*10^4 N/C

4 0
3 years ago
Check my work please
katrin [286]

We can use the ideal gas equation which is expressed as PV = nRT. At a constant volume and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:

T1/P1 = T2/P2

P2 = T2 x P1 / T1

P2 = 273 x 340 / 713

<span>P2 = 130 kPa</span>

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Which factor indicates the amount of charge on the source charge?
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B. The number of field lines on the source charge.
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A 1.2kg ball rolls forward with an acceleration of 1.11 m/s. What is the net force on the ball
grandymaker [24]

Answer:

1.332 N

Explanation:

Net Force = Mass x Acceleration
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I'm so sorry if I'm wrong.

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