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3 years ago

Selena, who moves with the grace and fluid motions of a cat, has been described as

1 answer:

6 0

Porcine = of, affecting, or resembling a pig or pigs
Equine = of, relating, or affecting horses or other members of the horse family
Ursine = of, relating to, or resembling bears
Feline = Of, relating to, or affecting cats or other members of the cat family

Your answer is option "D. feline"

(definitions from "New Oxford American Dictionary)

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Given a particle that has the velocity v(t) = 3 cos(mt) = 3 cos (0.5t) meters, a. Find the acceleration at 3 seconds. b. Find th

DiKsa [7]

Answer:

a. $\rm -1.49\ m/s^2.$

b. $\rm 50.49\ m.$

Explanation:

<u>Given:</u>

Velocity of the particle, v(t) = 3 cos(mt) = 3 cos (0.5t) .

The acceleration of the particle at a time is defined as the rate of change of velocity of the particle at that time.

$\rm a = \dfrac{dv}{dt}\\=\dfrac{d}{dt}(3\cos(0.5\ t ))\\=3(-0.5\sin(0.5\ t.))\\=-1.5\sin(0.5\ t).$

At time t = 3 seconds,

$\rm a=-1.5\sin(0.5\times 3)=-1.49\ m/s^2.$

<u>Note</u>:<em> The arguments of the sine is calculated in unit of radian and not in degree.</em>

The velocity of the particle at some is defined as the rate of change of the position of the particle.

$\rm v = \dfrac{dr}{dt}.\\\therefore dr = vdt\Rightarrow \int dr=\int v\ dt.$

For the time interval of 2 seconds,

$\rm \int\limits^2_0 dr=\int\limits^2_0 v\ dt\\r(t=2)-r(t=0)=\int\limits^2_0 3\cos(0.5\ t)\ dt$

The term of the left is the displacement of the particle in time interval of 2 seconds, therefore,

$\Delta r=3\ \left (\dfrac{\sin(0.5\ t)}{0.05} \right )\limits^2_0\\=3\ \left (\dfrac{\sin(0.5\times 2)-sin(0.5\times 0)}{0.05} \right )\\=3\ \left (\dfrac{\sin(1.0)}{0.05} \right )\\=50.49\ m.$

It is the displacement of the particle in 2 seconds.

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3 years ago

The diagram below shows the relative positions of Earth and the Sun at a certain time of the year. Based on the diagram, which s

AlladinOne [14]

Answer:

summer

Explanation:

Notice the higher density of the rays of the sun hitting straight the latitudes below the equator.

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3 years ago

How long does it take long a light from the sun to reach the earth if it travels a distance of 1.5 × 10^11m? (velocity of light

mojhsa [17]

Answer:

Therefore, light travelling at 3.0x10^8 meters per second takes 500 seconds (8 minutes, 20 seconds) to reach the Earth, which is 1.5x10^11 meters away from the sun

Explanation:

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2 years ago

The gasoline in a car does 40,000 J of work on a car and generates a constant force of 20 N. How far did the car go?

AnnyKZ [126]

L=F•d=>d=L/F=40,000/20=2,000 m

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3 years ago

Spiderman has a mass of 80 kg. He knows his webbing will break if it is exposed to a 200 N force. What is the maximum height he

likoan [24]

Answer:

This depends on the writers

if they want they can make spiderman deny the laws of nature

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3 years ago