Answer: 1477.78 N
Explanation:
Let's assume that the cross sectional area of the smaller piston be A1
let's also assume the cross sectional area of the larger piston be A2
We assume the force applied to the smaller piston be F1
We also assume the force applied to the larger piston be F2
we then use the formula
F1/A1 = F2/A2
From our question,
The radius of the smaller piston is 5 cm = 0.05 m
The radius of the larger piston is 15 cm = 0.15 m
The force of the larger piston is 13300 N
The force of the smaller piston is unknown = F
A1 = πr² = 3.142 * 0.05² = 0.007855 m²
A2 = πr² = 3.142 * 0.15² = 0.070695 m²
F1/0.007855 = 13300/0.070695
F1 = (13300 * 0.007855) / 0.070695
F1 = 104.4715 / 0.070695
F1 = 1477.78 N
Thus, the force the compressed air must exert is 1477.78 N
<span>An efect could be that sence the air us blowing on the hot tea that Nya has, an efect could be the temperatures mixing and the tea cooling down enough for Nya to drink</span>
Answer:
3 : 08 : 10.9
Explanation:
assuming a 12 hour clock
angular velocity of the hour hand is 2π/(3600(12)) rad/s
angular velocity of the minute hand is 2π/3600 rad/s
difference is 2π/3600 - 2π/(3600(12)) = 11(2π/(3600(12)) rad/s
45° = π/4 radians
This angle is covered in a time of
π/4 rad / 22π / (3600(12)) = 900(12) / 22 = 490.909090... s
or about 8 minutes 10.9 s
ANSWER 3:08:10.9
I believe the correct answer from the choices listed above is the third option. The device you found was a radiosonde. It is <span>a battery-powered telemetry instrument package carried into the atmosphere usually by a weather balloon that measures various atmospheric parameters. Hope this answers the question. Have a nice day.</span>
