Answer:
vₓ = 0.566 m / s, W_total = 9.1 J
Explanation:
This exercise is a parabolic type movement, for the x axis where there is no acceleration
x = v t
vₓ = x / t
vₓ = 0.34 / 0.6
vₓ = 0.566 m / s
the work done is
X axis
In this axis there is no acceleration, therefore the sum of the forces is zero and since the work is the force times the distance, we conclude that the lock in this axis is zero.
W₁ = 0
Y axis
in this axis the force that exists is the force of gravity, that is, the weight of the body
W₂ = Fy y
W₂ = mg and
W₂ = m 9.8 0.70
W₂ = m 9.1
the work is a scalar for which we have to add the quantities obtained
W_total = W₁ + W₂
W_total = 0 + 9.1 m
W_total = 9.1 m
In order to complete the calculation, the mass of the body is needed if we assume that the mass is m = 1
W_total = 9.1 J
It's really hard to make out the gibberish at the end, where the list of choices should be.
Here are the three equations for the relationships among the wavelength, frequency, and wave-speed, for ANY wave:
-- Speed = (wavelength) x (frequency)
-- Wavelength = (Speed) / (frequency)
-- Frequency = (Speed) / (wavelength)
Notice that you only have to remember any ONE of these. Then you can always get the other ones by multiplying or dividing both sides by the same quantity.
If you want to remember all of them, here are the short forms:
V = L · f
L = V / f
f = V / L
Answer:
(a). The time constant of the circuit is 2.17.
(b). The potential difference across the capacitor at t=17.0 s is 0.0396 V.
Explanation:
Given that,
Initial potential difference = 100 V
Potential difference across the capacitor = 1.00 V
(a). We need to calculate the time constant of the circuit
Using formula of potential difference

Put the value into the formula


On taking ln



(b). We need to calculate the potential difference across the capacitor at t=17.0 s
Using formula again


Hence, (a). The time constant of the circuit is 2.17.
(b). The potential difference across the capacitor at t=17.0 s is 0.0396 V.
(a) James has the most momentum which is 294 kgm/s.
(b) The resultant force acting on Basma is 90.78 N.
(c) The time taken for James to stop is 3.2 seconds.
<h3>
Momentum of each person</h3>
Momentum of James: P = mv = 98 x 3 = 294 kgm/s
Momentum of Basma: P = mv = 59 x 4 = 236 kgm/s
<h3>Resultant force of Basma</h3>
F = ma = mv/t = P/t = 236/2.6 = 90.78 N
<h3>Time for James to stop</h3>
F = P/t
t = P/F
t = 294/90.78
t = 3.2 s
Learn more about momentum here: brainly.com/question/7538238
#SPJ1
Answer:
The combined speed of camper and canoe is 1.71 m/s.
Explanation:
Given that,
Mass of camper 1, m = 100 kg
Speed of camper 1, v = 3 m/s
The combined mass of another camper and canoe is, M = 175 kg
We need to find the combined speed of camper and canoe. According to the conservation of linear momentum, the momentum of first camper is equal to linear momentum of the canoe and the second camper.

So, the combined speed of camper and canoe is 1.71 m/s.