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2 years ago

Why are experiments often performed in laboratories?

Physics

2 answers:

Reptile [31]2 years ago

8 0

The correct answer is B. You can control variables more easily.

Explanation:

In an experiment, scientists or researchers need to keep most of the variables or factors constant because only by doing this they can study the main factor or variable (dependent variable) in relation to the variable that is manipulated by the researcher (independent variable).

All of this is quite challenging in natural spaces because there are many variables and these cannot be controlled. For example, if the scientist wants to study how air humidify affects plant growth he/she needs to consider and control other factors such as light exposure, soil, weather changes, among others. On the opposite, in a laboratory or artificial environment, these variables can be more easily controlled as these are created by the scientist and not by nature. Thus, the reason experiments are often performed in laboratories is "You can control variables more easily".

kap26 [50]2 years ago

4 0

In my opinion,I think the answer is b.You can control variables more easily by doing different things for different purposes.

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Physics is explicitly involved in studying which of these activities?

Dmitrij [34]

Hey Friends
The answer to this question would be C
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3 years ago

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Which vector best represents the net force acting on the +3 C charge

adelina 88 [10]

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3 years ago

Use the worked example above to help you solve this problem. An Alaskan rescue plane drops a package of emergency rations to str

Vlad [161]

Answer:

(a) The package lands 682 meters horizontally ahead from the point the package was dropped from the plane

(b) The horizontal component = 39.0 m/s

The vertical component = 171.55 m/s

Explanation:

The parameters given are;

Velocity of the plane, vₓ = 39.0 m/s

Height of the plane above the ground, h = 1.50 × 10² m = 1,500 m

(a) The time, t, before the package hits the ground when dropped from the plane is given by the relation;

h = u·t + 1/2×g×t²

Where:

g = Acceleration due to gravity = 9.81 m/s²

u = Initial vertical velocity = 0 m/s

Hence;

1500 = 0×t + 1/2 × 9.81 × t² = 4.905·t²

∴ t = √(1500/4.905) = 17.49 s

The horizontal distance the package travels before landing = 17.49 × 39 ≈ 682 m

The package lands 682 meters horizontally ahead from the point the package was dropped from the plane

(b) The vertical velocity, $v_y$ , of the package just before landing is given by the relation;

$v_y$ ² = u² + 2·g·h

u = 0 m/s

∴ $v_y$ ² = 0 + 2×9.81×1500 = 29430 m²/s²

$v_y$ = √29430 = 171.55 m/s

Hence the horizontal component = 39.0 m/s

The vertical component = 171.55 m/s

$tan \theta = \dfrac{v_y}{v_x} = \dfrac{171.55}{39.0 } = 4.4$

∴ θ = tan⁻¹(4.4) = 77.19°.

6 0

3 years ago

How much watt is called 1 H. P

agasfer [191]

Answer:

746 watts

Explanation:

7 0

2 years ago

Multiple-Concept Example 13 presents useful background for this problem. The cheetah is one of the fastest accelerating animals,

Andre45 [30]

Answer:

9241.6 W or 12.39318 hp

Explanation:

u = Initial velocity = 0

v = Final velocity

m = Mass

t = Time taken

Energy

$KE=\frac{1}{2}m(v^2-u^2)\\\Rightarrow KE=\frac{1}{2}108(30.4^2-0^2)\\\Rightarrow KE=49904.64\ Joules$

Power

$P=\frac{KE}{t}\\\Rightarrow P=\frac{49904.64}{5.4}\\\Rightarrow P=9241.6\ W$

Converting to hp

$1\ W=\frac{1}{745.7}\ hp$

$\\\Rightarrow 9241.6\ W=\frac{9241.6}{745.7}\ hp=12.39318\ hp$

The power developed by the cheetah is 9241.6 W or 12.39318 hp

7 0

3 years ago