All categories

3 years ago

Why are experiments often performed in laboratories?

Physics

2 answers:

Reptile [31]3 years ago

8 0

The correct answer is B. You can control variables more easily.

Explanation:

In an experiment, scientists or researchers need to keep most of the variables or factors constant because only by doing this they can study the main factor or variable (dependent variable) in relation to the variable that is manipulated by the researcher (independent variable).

All of this is quite challenging in natural spaces because there are many variables and these cannot be controlled. For example, if the scientist wants to study how air humidify affects plant growth he/she needs to consider and control other factors such as light exposure, soil, weather changes, among others. On the opposite, in a laboratory or artificial environment, these variables can be more easily controlled as these are created by the scientist and not by nature. Thus, the reason experiments are often performed in laboratories is "You can control variables more easily".

kap26 [50]3 years ago

4 0

In my opinion,I think the answer is b.You can control variables more easily by doing different things for different purposes.

You might be interested in

Free coins be quick to get them

olga nikolaevna [1]

Answer:

yeetshhdbdbdhdhdxsudhhdbdjdjd

7 0

2 years ago

Read 2 more answers

A block–spring system vibrating on a frictionless, horizontal surface with an amplitude of 7.0 cm has an energy of 14 J. If the

Bingel [31]

Answer:

$E_T= 28J$

Explanation:

The energy of Mass-Spring System the sum of the potential energy of the block plus the kinetic energy of the block:

$E_T=U+K=\frac{1}{2} k \Delta x^2+\frac{1}{2} mv^2$

Where:

$\Delta x=Amplitude\hspace{3}or\hspace{3}d eformation\hspace{3} of\hspace{3} the\hspace{3} spring\\m=Mass\hspace{3}of\hspace{3}the\hspace{3}block\\k=Constant\hspace{3}of\hspace{3}the\hspace{3}spring\\v=Velocity\hspace{3}of\hspace{3}the\hspace{3}block$

There are two cases, the first case is when the spring is compressed to its maximum value, in this case the value of the kinetic energy is zero, since there is no speed, so:

$E_T=\frac{1}{2} k \Delta x^2\\\\14=\frac{1}{2} k7^2\\\\Solving\hspace{3} for\hspace{3} k\\\\k=\frac{28}{49} =\frac{4}{7}$

The second case is when the block passes through its equilibrium position, in this case the elastic potential energy is zero since $\Delta x=0$ , so:

$E_T=\frac{1}{2} mv^2\\\\14=\frac{1}{2} mv^2\\\\Solving\hspace{3} for\hspace{3} v\\\\v^2=\frac{28}{m}$

Now, let's find the energy of the system when the block is replaced by one whose mass is twice the mass of the original block using the previous data:

$E_T=U+K=\frac{1}{2} k \Delta x^2+\frac{1}{2} m_2v^2$

Where in this case:

$m_2=New\hspace{3}mass=Twice\hspace{3} the\hspace{3} mass \hspace{3}of\hspace{3} the\hspace{3} original=2m$

Therefore:

$E_T=\frac{1}{2} (\frac{4}{7} ) (7^2)+\frac{1}{2} (2m)(\frac{28}{m_2})=\frac{1}{2} (\frac{4}{7} ) (7^2)+\frac{1}{2} (2m)(\frac{28}{2m})=14+14=28J$

8 0

3 years ago

in a circuit, where do electric charges go once they have left the voltage source and traveled along the wires?

S_A_V [24]

In an electric circuit, the free electrons are moving around. Since equal charges repel and opposite charges attract, the electrons move from the negatively charged to the positively charged pole of the voltage source.

7 0

2 years ago

The image below shows two opposite forces acting on a rope, what can we say is true about the affect of the forces on the rope?

Tamiku [17]

It would be D) the rope is pulled to the right. This is because their is a greater force in that direction.

8 0

3 years ago

Read 2 more answers

How are electric fuses rated

vitfil [10]

Answer:

The fuse rating can be calculated by dividing the power used by the appliance by the voltage going into the appliance.

Explanation:

(AMPS)=P(watts)÷V(Voltage)

6 0

2 years ago