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3 years ago

Why are experiments often performed in laboratories?

Physics

2 answers:

Reptile [31]3 years ago

8 0

The correct answer is B. You can control variables more easily.

Explanation:

In an experiment, scientists or researchers need to keep most of the variables or factors constant because only by doing this they can study the main factor or variable (dependent variable) in relation to the variable that is manipulated by the researcher (independent variable).

All of this is quite challenging in natural spaces because there are many variables and these cannot be controlled. For example, if the scientist wants to study how air humidify affects plant growth he/she needs to consider and control other factors such as light exposure, soil, weather changes, among others. On the opposite, in a laboratory or artificial environment, these variables can be more easily controlled as these are created by the scientist and not by nature. Thus, the reason experiments are often performed in laboratories is "You can control variables more easily".

kap26 [50]3 years ago

4 0

In my opinion,I think the answer is b.You can control variables more easily by doing different things for different purposes.

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Imagine that asteroid A that has an escape velocity of 50 m/s. If asteroid B has twice the mass and twice the radius, it would h

padilas [110]

Answer:

The same as the escape velocity of asteorid A (50m/s)

Explanation:

The escape velocity is described as follows:

$v=\sqrt{\frac{2GM}{R}}$

where $G$ is the universal gravitational constant, $M$ is the mass of the asteroid and $R$ is the radius

and since the scape velocity is 50m/s:

$50m/s=\sqrt{\frac{2GM}{R}}$

Now, if the astroid B has twice mass and twice the radius, we have that tha mass is: $2M$

and the radius is: $2R$

inserting these values into the formula for escape velocity:

$v=\sqrt{\frac{2G(2M)}{2R} } =\sqrt{\frac{4GM}{2R} } =\sqrt{\frac{2GM}{R} }$

and we have found that $50m/s=\sqrt{\frac{2GM}{R}}$ , so the two asteroids have the same escape velocity.

We found that the expression for escape velocity remains the same as for asteroid A, this because both quantities (radius and mass) doubled, so it does not affect the equation.

The answer is

Asteroid B would have an escape velocity the same as the escape velocity of asteroid A

7 0

3 years ago

Suppose an air bubble is trapped in the eudiometer before starting the experiment. After the experiment is finished, the resulti

seraphim [82]

Answer:

Explanation:

The resulting valie would be too large

8 0

2 years ago

an object at rest will remain at rest and an object in motion stays in straight-line motion unless acted upon by a_____ or unbal

LekaFEV [45]

Equal is the answer your looking for

5 0

3 years ago

A key falls from a bridge that is 45 m above the water. It falls directly into a model boat, moving with constant velocity, that

guapka [62]

Answer:

4m/s

Explanation:

The motion is in downward direction, and the boat is moving with constant velocity, the position of the boat horizontally is 12m before the key fall.

The height difference "h"= ( y- y°)= 45 m

We can determine the needed time the key requires to reach the water using the expression from Newton's law

h= v(o) + 1/2 at^2

g= acceleration due to gravity= 9.8m/s^2

h= v(o) + 1/2 gt^2 -------------------------eqn*)

V(o)= 0 for the key= initial velocity

h= height that the key falls= 45m

If we substitute the above values into eqn(*) we have

We can make t^2 subject of the formula since v(0)= 0

t^2= h/(1/2 g)

= 45/(1/2× 9.8)

t^2= 45/4.9=9.18

t= √9.18

t=3.03 secs

Since the boat was moving with constant velocity,

Then Velocity= distance/ time

= 12/3.03

Velocity= 4m/s

Hence, the speed of the boat is 4m/s

7 0

3 years ago

An object is place 30.5 cm from a convex lens that has a focal length of 8.0cm.where is the image ?

77julia77 [94]

Answer:

Image is between F and 2F. And the exact location is:

q = 10.84 cm

Explanation:

The convex lens form different kinds of images with different sizes and locations, for the different positions of an object. In this case, the object is placed 30.5 cm from the convex lens with a focal length of 8 cm. This means that it is the case of the object placed beyond 2F. In this case, the image formed has the following characteristics:

1. Image is real.

2. Image is inverted

3. Image is diminished

<u>4. Image is located between F and 2F</u>

For exact location we use the thin lens formula:

$\frac{1}{f} = \frac{1}{p} + \frac{1}{q}$

where,

f = focal length = 8 cm

p = object distance = 30.5 cm

q = image distance = ?

Therefore,

$\frac{1}{8\ cm} = \frac{1}{30.5\ cm} + \frac{1}{q} \\\frac{1}{8\ cm} - \frac{1}{30.5\ cm} = \frac{1}{q}$

7 0

2 years ago