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BARSIC [14]
3 years ago
12

Help? Q1 Given the following data: 18, 47, 51, 60, 72, 75, 80 Find Q1 =

Mathematics
1 answer:
Andrej [43]3 years ago
6 0

Answer:

47

Step-by-step explanation:

Q1 is half the first half of the data

18, 47, 51, [60], 72, 75, 80

^center, (Q2)

^Q1

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If qr+4p=12, what is the value of q in terms of p and r ?
Andreyy89

Answer:

q=\frac{12-4p}{r}

Step-by-step explanation:

qr+4p=12\\=> qr=12-4p\\=> q =\frac{12-4p}{r}

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3 years ago
A right circular cone is intersected by a plane that passes through the cone's
yarga [219]

Answer:

  B.  A pair of intersecting lines

Step-by-step explanation:

The attached image can give you an idea of what you get when a plane perpendicular to the base of a cone intersects the vertex of the cone.

__

In the problem statement here, we assume a double-napped cone with no defined base. That means the lines of intersection with the sides of the cone will meet at the vertex point and extend indefinitely in either direction.

The intersection is a pair of intersecting lines.

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2 years ago
Accountancy
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2 years ago
3. A regular pentagon has a perimeter of 10x + 15. What is the length of che side?
Ivan

Answer:

C

Step-by-step explanation:

A pentagon has 5 sides. Given that it is a regular pentagon, these 5 sides are equal.

The perimeter is the total length of all the sides of the pentagon. Since these 5 sides are all equal, we can divide the perimeter by 5 to obtain the length of a side of the pentagon.

Perimeter= 10x +15

Length of each side

= (10x +15) ÷5

= 2x +3

5 0
3 years ago
In Exercises 10 and 11, points B and D are points of tangency. Find the value(s) of x.<br>​
Lemur [1.5K]

In both cases,

AB^2=AD^2

(as a consequence of the interesecting secant-tangent theorem)

So we have

10.

(4x+7)^2=(6x-3)^2

16x^2+56x+49=36x^2-36x+9

20x^2-92x-40=0

5x^2-23x-10=0

(5x+2)(x-5)=0\implies\boxed{x=5}

(omit the negative solution because that would make at least one of AB or AD have negative length)

11.

(4x^2-18x-10)^2=(x^2+x+4)^2

16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16

15x^4-146x^3+235x^2+352x+84=0

(x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}

(again, omit the solutions that would give a negative length for either AB or AD)

7 0
3 years ago
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