Answer :
(a). The speed of the block is 0.395 m/s.
(b). No
Explanation :
Given that,
Diameter = 20.0 cm
Power = 26.0 MW
Mass = 110 kg
diameter = 20.0 cm
Distance = 100 m
We need to calculate the pressure due to laser
Using formula of pressure

![P_{r}=\dfrac{P}{Ac}Put the value into the formula[tex]P_{r}=\dfrac{26.0\times10^{6}}{\pi\times(10\times10^{-2})^2\times3\times10^{8}}](https://tex.z-dn.net/?f=P_%7Br%7D%3D%5Cdfrac%7BP%7D%7BAc%7D%3C%2Fp%3E%3Cp%3EPut%20the%20value%20into%20the%20formula%3C%2Fp%3E%3Cp%3E%5Btex%5DP_%7Br%7D%3D%5Cdfrac%7B26.0%5Ctimes10%5E%7B6%7D%7D%7B%5Cpi%5Ctimes%2810%5Ctimes10%5E%7B-2%7D%29%5E2%5Ctimes3%5Ctimes10%5E%7B8%7D%7D)

We need to calculate the force
Using formula of force


Put the value into the formula


We need to calculate the acceleration
Using formula of force

Put the value into the formula




(a). We need to calculate speed of the block
Using equation of motion

Put the value into the formula


(b). No because the velocity is very less.
Hence, (a). The speed of the block is 0.395 m/s.
(b). No
Answer: d)
Explanation: In order to justify the answer we have to consider that the energy of photons directely depent on the frequency so the energy is inverselly dependent of the wavelegth.
If both beams have the same power, this means Energy/time so the number of photons per second must be different. As consequence a) is wrong as b) since it is not posible since UV photon have more energy that IR photons. c) It is no necessary know the frequency since the wavelength is related in the form:
c=λν c is the speed of light, λ the wavelegth and ν the frequency.
d) Certainly will be more more IR photons than UV photons to get the same beam power.
Let the angle be Θ (theta)
Let the mass of the crate be m.
a) When the crate just begins to slip. At that moment the net force will be equal to zero and the static friction will be at the maximum vale.
Normal force (N) = mg CosΘ
μ (coefficient of static friction) = 0.29
Static friction = μN = μmg CosΘ
Now, along the ramp, the equation of net force will be:
mg SinΘ - μmg CosΘ = 0
mg SinΘ = μmg CosΘ
tan Θ = μ
tan Θ = 0.29
Θ = 16.17°
b) Let the acceleration be a.
Coefficient of kinetic friction = μ = 0.26
Now, the equation of net force will be:
mg sinΘ - μ mg CosΘ = ma
a = g SinΘ - μg CosΘ
Plugging the values
a = 9.8 × 0.278 - 0.26 × 9.8 × 0.96
a = 2.7244 - 2.44608
a = 0.278 m/s^2
Hence, the acceleration is 0.278 m/s^2
The answer would be tectonic. hope this helps (:
Answer:
The box displacement after 6 seconds is 66 meters.
Explanation:
Let suppose that velocity given in statement represents the initial velocity of the box and, likewise, the box accelerates at constant rate. Then, the displacement of the object (
), in meters, can be determined by the following expression:
(1)
Where:
- Initial velocity, in meters per second.
- Time, in seconds.
- Acceleration, in meters per square second.
If we know that
,
and
, then the box displacement after 6 seconds is:

The box displacement after 6 seconds is 66 meters.