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2 years ago

10

An x-ray and a radio wave are both shot into outer space (they both travel in vacuum). What is the difference between the two si

gnals? Select all that apply. *
x-ray has a higher frequency
x-ray has more energy
x-ray is faster
x-ray has a higher wavelength

1 answer:

daser333 [38]2 years ago

4 0

Answer:

AB

Explanation:

Same speed. Shorter wavelengths.

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A lamp is 10% efficient.How much electrical energy must be supplied to the lamp each second if it produces 20 J of light energy

k0ka [10]

If it produces 20J of light energy in a second, then that 20J is the 10% of the supply that becomes useful output.

20 J/s = 10% of Supply

20 J/s = (0.1) x (Supply)

Divide each side by 0.1:

Supply = (20 J/s) / (0.1)

<em>Supply = 200 J/s </em>(200 watts)

========================

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Read 2 more answers

An investigator places a sample 1.0 cm from a wire carrying a large current; the strength of the magnetic field has a particular

Sonja [21]

Answer: <em>she will have to increase the factor of current by</em> 11

Explanation: The mathematical relationship between the strength of the magnetic field (B) created by a current carrying conductor with current (I) is given by the Bio-Savart law given below

B= $\frac{u_{0}I }{2\pi r}$

B=strength of magnetic field

I = current on conductor

r = distance on any point of the conductor from it center

u $_{0}$ = permeability of magnetic field in space

from the question, the investigator is trying to keep a constant magnetic field meaning B has a fixed value such as the constants in the formulae, the only variables here are current (I) and distance (r). We can get this a mathematical function.

by cross multipying, we have

B* 2πr= $u_{0}$ <em>I </em>

by dividing through to make <em>I </em>subject of formulae, we have that

<em>I </em>= $\frac{B*2\pi r}{u_{0} }$

B, 2π and $u_{0}$ are all constants, thus

$\frac{B*2\pi r}{u_{0} }$ = k(constant)

thus we have that

<em>I </em>=kr<em> (current is proportional to distance assuming magnetic field strength and other parameters are constant) </em>

thus we have that

$\frac{I_{1} }{r_{1} }$ = $\frac{I_{2} }{r_{2} }$

$r_{1}$ =1cm and $r_{2}$ =11cm

$\frac{1_{1} }{1}$ = $\frac{I_{2} }{11}$

thus $I_{2}$ =11* $I_{1}$

which means the second current is 11 times the first current

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3 years ago