All categories

3 years ago

Please help, will reward brainliest.

Mathematics

1 answer:

Gekata [30.6K]3 years ago

4 0

Answer:

2 out of every 5; 2:3; 2:5

Step-by-step explanation:

2 out of every 5 means that out of 5, he/she picks two (leftover 3)

the other choices are a ratio of if he/she has 2 of that then they will also have 5 of this

You might be interested in

Where was the first place math was found?

Flauer [41]

Answer:

Mesopotamia

Step-by-step explanation:

The oldest clay tablets with mathematics date back over 4,000 years ago in Mesopotamia. The oldest written texts on mathematics are Egyptian papyruses.

8 0

3 years ago

Add. (3b + 5) + (2b + 4)

zaharov [31]

Answer:

$\huge{ \fbox{ \sf{5b + 9}}}$

Step-by-step explanation:

$\star{ \text{( \: 3b + 5) + (2b + 4)}}$

$\text{Step \: 1 \: : \sf{Remove \: the \: unnecessary \: parentheses}}$

$\text{When \: there \: is \: a \: ( + ) \: in \: front \: of \: an \: expression \: in \: parentheses \:, there \: is \: no \: need \: to \: change \: the \: sign \: of \: each \: term \: in \: the \: expression.}$

$\text{That \: means, \: the \: expression \: remains \: the \: same. \: Just \: you \: have \: to \: remove \: the \: parentheses.}$

$\mapsto{ \sf{3b + 5 + 2b + 4}}$

$\text{Step \: 2 \: : Collect \: like \: terms.}$

$\text{Like \: terms \: are \: those \: which \: have \: the \: same \: base.}$

$\mapsto{ \sf{3b + 2b + 5 + 4}}$

$\mapsto{ \sf{5b + 5 + 4}}$

$\text{ Step \: 3 \: : \sf{Add \: the \: numbers : 5 \: and \: 4}}$

$\mapsto{ \boxed {\sf{ {5b + 9}}}}$

Hope I helped!

Best regards! :D

~ $\sf{TheAnimeGirl}$

4 0

3 years ago

true or false. for a continuous function, of f(2) is negative and f(3) is positive, then there must be a zero between x=2 and x=

Rashid [163]

It's true. In general, if a function is continuous, and you have

$f(x_1)=y_1,\quad f(x_2)=y_2$

then $f(x)$ spans all the possible values between $y_1$ and $y_2$ in the interval $[x_1,x_2]$

So, in particular, if you have

$f(2) = y_2 < 0,\quad f(3) = y_3 > 0$

you can conclude that in the interval $[2,3]$ , $f(x)$ span all the values between $y_2$ and $y_3$ , which include 0 because $y_2$ is negative and $y_3$ is negative.