Answer:
The final speed of the electron = 2.095×10⁸ m/s
Explanation:
From newton's fundamental equation of dynamics,
F = ma ........................Equation 1
Where F = force, m = mass of the electron, a = acceleration of the electron.
making a the subject of the equation,
a = F/m.................... Equation 2
Given: F = 4.0×10⁻¹⁵ N,
Constant: m = 9.109×10⁻³¹ kg.
Substituting into equation 2
a = 4.0×10⁻¹⁵/9.109×10⁻³¹
a = 4.39×10¹⁶ m/s².
Using newton's equation of motion,
v² = u²+2as .......................... Equation 3
Where v = final velocity of the electron, u = initial velocity of the electron, a = acceleration of the electron, s = distance covered by the electron.
Given: u = 0 m/s(at rest), s = 50 cm = 0.5 m, a = 4.39×10¹⁶ m/s²
Substituting into equation 3
v² = 0² + 2(0.5)(4.39×10¹⁶)
v = √(4.39×10¹⁶)
v = 2.095×10⁸ m/s
Thus the final speed of the electron = 2.095×10⁸ m/s
