You shall use the equation for force given by the second Law of Newton, this is F = m*a, where F is the net force that acts over the object, m is the mass of the object and a is the acceleration that the object will acquire. From that equation you can find a = F/m, which means that a is direct proportional to F and invsersely related to m. So, small masses accelerate faster than large masses, and <span>the answer is the option B. the small mass accelerates faster.</span>
Answer:
a) w = 9.599 10⁴ rad / s
, b) v = 3.35 10¹⁶ m / s
, c) a = 3.22 10²¹ m / s²
Explanation:
For this exercise we must use the relation of angular kinematics
a) angular velocity, the distance remembered in orbit between time (period)
w = 2π r / T
w = 2 π 3.59 10¹¹ / 2.35 10⁷
w = 9.599 10⁴ rad / s
b) linear and angular velocity are related by the equation
v = w r
v = 9,599 10⁴ 3.49 10¹¹
v = 3.35 10¹⁶ m / s
c) the centripetal acceleration is
a = v² / r = w² r
a = (9,599 10⁴)² 3.49 10¹¹
a = 3.22 10²¹ m / s²
Answer:
50m; 0m/s.
Explanation:
Given the following data;
Initial velocity = 20m/s
Acceleration, a = - 4m/s²
Time, t = 5secs
To find the displacement, we would use the second equation of motion;
Substituting into the equation, we have;
S = 50m
Next, to find the final velocity, we would use the third equation of motion;
Where;
- V represents the final velocity measured in meter per seconds.
- U represents the initial velocity measured in meter per seconds.
- a represents acceleration measured in meters per seconds square.
<em>Substituting into the equation, we have;</em>
V = 0m/s
<em>Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.</em>
The best answer is B. If you curve them away, they have a less tendency to be attracted to the pair of charges and would stay around the pair instead of interacting with them.
