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timofeeve [1]
2 years ago
7

Red light Green light is used to work on what skill?

Physics
2 answers:
prisoha [69]2 years ago
6 0

Answer:

Dribbling

Explanation:

cuz yes, is answer took test

Talja [164]2 years ago
4 0
Running for sure ptttt
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Suppose wave pulses in an aquarium are produced by a mechanical motor that moves a bob up and down at the surface. The setup use
-Dominant- [34]

Answer:

kinetic energy in each pulse = 9.5J

Explanation:

  • The concept used here is that of work, energy and power.

  • Power P = Work /Time

  • Work = energy in this case

  • E = Power x time = Pt

  • but Power = 10W and t = 1.9s

  • Energy E = 10W x 1.9s = 19J

Conventionally, overall energy = kinetic + potential

Hence kinetic energy in each pulse = half of the total energy = 0.5 x 19

energy = 9.5J

3 0
3 years ago
Radio waves coming from a radio station are tuned into by a student in class. What form of energy transfer does the radio statio
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Radio waves are a type of electromagnetic (EM) radiation with wavelengths in the electromagnetic spectrum longer than infrared light.
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3 years ago
Select all that apply. Marks of the Gupta society included: all male citizens could own property an established caste system wom
77julia77 [94]
<span>choices are:
all male citizens could own property
an established caste system
women had creative Shakti that men didn't
the height of Hindu culture shunning of all religious beliefs and philosophies

ans are:
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8 0
3 years ago
Read 2 more answers
What occurs along a convergent plate?
Tasya [4]
Your answer is D. Earthquakes and hot spots occur along convergent plates. 
3 0
3 years ago
The magnetic dipole moment of Earth has magnitude 8.00 1022 J/T.Assume that this is produced by charges flowing in Earth’s molte
ziro4ka [17]

Answer:

2.08\cdot 10^9 A

Explanation:

The magnetic dipole moment of a circular coil with a current is given by

\mu = IA

where

I is the current in the coil

A=\pi r^2 is the area enclosed by the coil, where

r is the radius of the coil

So the magnetic dipole moment can be rewritten as

\mu = I\pi r^2 (1)

Here we can assume that the magnetic dipole moment of Earth is produced by charges flowing in Earth’s molten outer core, so by a current flowing in a circular path of radius

r=3500 km = 3.5\cdot 10^6 m

Here we also know that the Earth's magnetic dipole moment is

\mu = 8.0\cdot 10^{22} J/T

Therefore, we can re-arrange eq (1) to find the current that the charges produced:

I=\frac{\mu}{\pi r^2}=\frac{8.00\cdot 10^{22}}{\pi (3.5\cdot 10^6)^2}=2.08\cdot 10^9 A

3 0
3 years ago
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