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shtirl [24]
3 years ago
5

Smialarities between kinetic friction and static friction?

Physics
2 answers:
kiruha [24]3 years ago
6 0

Kinetic and static friction are both resistive forces

levacccp [35]3 years ago
6 0
Both static and kinetic friction are resistive forces.they act against movement or attempted movement between 2 surfaces that are in contact,proportional to the normal force between the 2 objects and their strength depends also on a coefficient of friction,which is unique for any two materials in contact.
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What is the efficient cause if acceleration​
vladimir1956 [14]

Answer:

acceleration= velocity ÷ time

Explanation:

the question is outrageous

4 0
3 years ago
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When an MRI machine are use to capturing images of a person's body the produce extremely powerful magnetic fields what might be
aliina [53]

Answer:

Technique to reduce Noise, magnetic attraction and Twitching sensation

Explanation:

Changing magnetic fields cause loud knocking noise this can be overcome by ear protection.

Strong and Static magnetic fields attract magnetic objects that can be avoided by screening of people and objects before entering in that area.

Twitching Sensation due to nerve stimulation can be avoided by reducing the exposure to magnetic field.

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4 0
2 years ago
Two cylinders A and B at the same temperature contain the same quantity of the same kind of gas. Cylinder A has three times the
astraxan [27]

Answer:

so pressure in A must be one third the pressure in B

Explanation:

We shall apply gas law to the cylinders A and B . Since their quantity are same so their no of  mole will also be same .

For cylinder A

Temperature T , volume 3V , pressure  P₁ , no of mole = n

so

P₁ X 3V = n R T

For cylinder B

Temperature T , volume V , pressure  P₂ ,no of  mole = n

so

P₂ X V = n R T

From the two equation above

P₁ X 3V = P₂ X V

\frac{P_1}{P_2}=\frac{1}{3}

P₁ = P₂ / 3

so pressure in A must be one third the pressure in B

3 0
3 years ago
A horizontal spring-mass system has low friction, spring stiffness 165 N/m, and mass 0.6 kg. The system is released with an init
AURORKA [14]

a) 19.4 cm

b) 3.2 m/s

Explanation:

a)

A horizontal spring-mass system has a motion called simple harmonic motion, in which the mass oscillates following a periodic function (sine or cosine) around an equilibrium position.

As the system oscillates back and forth, its total mechanical energy (sum of elastic potential energy and kinetic energy) will remain conserved (since we consider friction negligible). The elastic potential energy at any point is given by:

U=\frac{1}{2}kx^2

where

k is the spring constant

x is the displacement of the system

While the kinetic energy at any point is

K=\frac{1}{2}mv^2

where

m is the mass

v is the speed

So the total mechanical energy of the system is

E=K+U=\frac{1}{2}mv^2+\frac{1}{2}kx^2

For this system, when it is initially released,

m = 0.6 kg

k = 165 N/m

x = 7 cm = 0.07 m

v = 3 m/s

So the total energy is

E=\frac{1}{2}(0.6)(3)^2+\frac{1}{2}(165)(0.07)^2=3.1 J

Since friction is negligible, this total energy remains constant. Therefore, when the system reaches its maximum stretch during the motion, the kinetic energy will be zero and all the mechanical energy will be elastic potential energy; so we will have:

E=U=\frac{1}{2}kx_{max}^2

where x_{max} is the maximum stretch. Solving for x_{max},

x_{max}=\sqrt{\frac{2E}{k}}=\sqrt{\frac{2(3.1)}{165}}=0.194 m

So, 19.4 cm.

b)

The maximum speed in a spring-mass oscillating system is reached when the kinetic energy is maximum, and therefore, since the total energy is conserved, when the elastic potential energy is zero:

U=0

which means when the displacement is zero:

x = 0

So, when the system is transiting through the equilibrium position.

Therefore, the total mechanical energy is equal to the maximum kinetic energy:

E=K=\frac{1}{2}mv_{max}^2

where

m is the mass

v_{max} is the maximum speed

Here we have:

E = 3.1 J

m = 0.6 kg

Therefore, solving for the maximum speed,

v_{max}=\sqrt{\frac{2E}{m}}=\sqrt{\frac{2(3.1)}{0.6}}=3.2 m/s

6 0
4 years ago
A recipe for a casserole calls for 1 cup of milk. If a chef currently has 0.5 gallons of milk, how many casseroles can the chef
Yakvenalex [24]

Answer:

<em>The chef can make 8 casseroles</em>

Explanation:

<u>Units Conversion</u>

We need to recall 1 gallon = 16 US cups.

A casserole needs 1 cup of milk, and the chef has 0.5 gallons of milk. Those 0.5 gallons are equivalent to 0.5*16 = 8 cups, thus the chef can make 8 casseroles.

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