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3 years ago

Smialarities between kinetic friction and static friction?

Physics

2 answers:

kiruha [24]3 years ago

6 0

Kinetic and static friction are both resistive forces

levacccp [35]3 years ago

6 0

Both static and kinetic friction are resistive forces.they act against movement or attempted movement between 2 surfaces that are in contact,proportional to the normal force between the 2 objects and their strength depends also on a coefficient of friction,which is unique for any two materials in contact.

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Does the lattice energy of an ionic solid increase or decrease as the charges or sizes of the ions increase?

alexandr1967 [171]

Answer:

Explanation:

Lattice energy is the energy required to separate one mole of an ionic solid compound into its components gaseous cations and anions.

Due to increase in size of the ions, the lattice energy decreases while the lattice energy increases as the charge of the ions increases.

When the size increase, the distance between the nuclei also increase leading a decrease the force of attraction between the nuclei

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3 years ago

What is heart sound?

Dafna11 [192]

Answer:

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3 years ago

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(6.MS-ETS2-1(MA).) The electrons in __________ move about more freely than the electrons in insulators which is why this type of

Tresset [83]

Answer:

A) conductors

Explanation:

A conductor can be defined as any material or object that allows the free flow of current or electrons (charge) in one or more directions in an electrical circuit. Some examples of a conductor are metals, tungsten, copper, aluminum, iron, graphite, etc.

Basically, the main purpose of a conductor in physics is to provide a low-resistance path between electrical circuits or components. This low-resistance path is to ensure that the electrical components allows the free flow of electrons and thus, enabling charge transfer.

Hence, the electrons in conductors move about more freely than the electrons in insulators which is why this type of material can be used to create electric circuits because it would significantly provide a low-resistance path between the electric circuits.

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2 years ago

A cylindrical capacitor has an inner conductor of radius 2.7 mmmm and an outer conductor of radius 3.1 mmmm. The two conductors

Mars2501 [29]

Answer:

(A) Capacitance per unit length = $4.02 \times 10^{-10}$

(B) The magnitude of charge on both conductor is $Q = 4.22 \times 10^{-19}$ C and the sign of charge on inner conductor is $+Q$ and the sign on outer conductor is $-Q$

Explanation:

Given :

Radius of inner part of conductor $(R_{1})$ = $2.7 \times 10^{-3}$ m

Radius of outer part of conductor $(R_{2})$ = $3.1 \times 10^{-3}$ m

The length of the capacitor $(l)$ = $3 \times 10^{-3}$ m

(A)

Capacitance is purely geometrical property. It depends only on length, radius of conductor.

From the formula of cylindrical capacitor,

$C = \frac{2\pi\epsilon_{o} l }{ln\frac{R_{2} }{R_{1} } }$

Where, $\epsilon_{o} = 8.85 \times 10^{-12}$

But we need capacitance per unit length so,

$\frac{C}{l} = \frac{2\pi\epsilon_{o} }{ln\frac{R_{2} }{R_{1} } }$

capacitance per unit length = $\frac{6.28 \times 8.85 \times 10^{-12} }{ln(1.148)} = 4.02 \times 10^{-10}$

(B)

The charge on both conductors is given by,

$Q = C \Delta V$

Where, C = capacitance of cylindrical capacitor and value of $C = 12.06 \times 10^{-13}$ F, $\Delta V = 350 \times 10^{-3}$ V

∴ $Q = 4.22 \times 10^{-19}$ C

The magnitude of charge on both conductor is same as above but the sign of charge is different.

Charge on inner conductor is $+Q$ and Charge on outer conductor is $-Q$ .

8 0

3 years ago

the car turned a corner going 10m/s if it took two seconds to turn what is its acceleration is this acceleration

exis [7]

The acceleration of this car is equal to 5 $m/s^2$ .

<u>Given the following data:</u>

Initial velocity = 0 m/s (assuming it's starting from rest).

Final velocity = 10 m/s.

Time = 2 seconds.

To determine the acceleration of this car:

<h3>How to calculate acceleration.</h3>

In Science, the acceleration of an object is calculated by subtracting the initial velocity from its final velocity and dividing by the time.

Mathematically, acceleration is given by this formula:

$a = \frac{V\;-\;U}{t}$

<u>Where:</u>

V is the final velocity.

U is the initial velocity.

is the time measured in seconds.

Substituting the given parameters into the formula, we have;

$a = \frac{10\;-\;0}{2}$

Acceleration, a = 5 $m/s^2$

Read more on acceleration here: brainly.com/question/24728358

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1 year ago