We are given a box that slides up a ramp. To determine the force of friction we will use the following relationship:

Where.

To determine the Normal force we will add the forces in the direction perpendicular to the ramp, we will call this direction the y-direction as shown in the following diagram:
In the diagram we have:

Adding the forces in the y-direction we get:

Since there is no movement in the y-direction the sum of forces must be equal to zero:

Now we solve for the normal force:

To determine the y-component of the weight we will use the trigonometric function cosine:

Now we multiply both sides by "mg":

Now we substitute this value in the expression for the normal force:

Now we substitute this in the expression for the friction force:

Now we substitute the given values:

Solving the operations:

Therefore, the force of friction is 15.01 Newtons.
Answer:
I think they are called balanced forces
Explanation:
Answer:
(A) V = 9.89m/s
(B) U = -2.50m/s
(C) ΔK.E = –377047J
(D) ΔK.E = –257750J
Explanation:
The full solution can be found in the attachment below. The east has been chosen as the direction for positivity.
This problem involves the principle of momentum conservation. This principle states that the total momentum before collision is equal to the total momentum after collision. This problem is an inelastic kind of collision for which the momentum is conserved but the kinetic energy is not. The kinetic energy after collision is always lesser than that before collision. The balance is converted into heat by friction, and also sound energy.
See attachment below for full solution.
Answer:
Explanation:
Given
mass of boy=36 kg
length of swing=3.5 m
Let T be the tension in the swing
At top point 
where v=velocity needed to complete circular path
Th-resold velocity is given by 

So apparent weight of boy will be zero at top when it travels with a velocity of 
To get the velocity at bottom conserve energy at Top and bottom
At top 
Energy at Bottom 
Comparing two as energy is conserved



Apparent weight at bottom is given by
