Answer:
The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.
Explanation:
Passengers which are facing forward in the direction that train is moving, their bodies will move forward in application of sudden stop of train.
<h3>What is force of inertia?</h3>
Force of inertia is the force which acts in the opposite direction of the force of acceleration acting on the body.
Given infroamtion-
The passengers are facing forward in the direction that the train is moving.
The train comes to a sudden stop.
Lets see what happens step wise-
- Here, the train in moving in the forward direction and the passengers are also facing forward in the direction that the train is moving.
- Now the train comes to a sudden stop. By this sudden stop the train stops suddenly but all the object including the passengers is still travelling forward due to the inertia force.
- Thus all the passenger will tend to move in the direction as they are still travelling.
Hence, passengers which are facing forward in the direction that train is moving, their bodies will move forward in application of sudden stop of train.
Learn more about the force of inertia here;
brainly.com/question/10454047
Will this one work?...................
Answer:
a)
s
b) 3.41 mm
Explanation:
a)
We take the speed of light, c =
m/s and the refractive index of glass as 1.517.
Speed = distance/time
Time = distance/speed
Refractive index, n = speed of light in vacuum / speed of light in medium
![n=\dfrac{c}{s}](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7Bc%7D%7Bs%7D)
![s=\dfrac{c}{n}](https://tex.z-dn.net/?f=s%3D%5Cdfrac%7Bc%7D%7Bn%7D)
![t=\dfrac{d}{c/n}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7Bd%7D%7Bc%2Fn%7D)
![t=\dfrac{dn}{c}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7Bdn%7D%7Bc%7D)
![t=\dfrac{3\times10^{-3}\times1.517}{3.0\times10^8}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7B3%5Ctimes10%5E%7B-3%7D%5Ctimes1.517%7D%7B3.0%5Ctimes10%5E8%7D)
![t=1.517\times10^{-11}](https://tex.z-dn.net/?f=t%3D1.517%5Ctimes10%5E%7B-11%7D)
b)
We take the refractive index of water as 1.333.
Speed in water = speed in vacuum / refractive index of water
Distance = speed * time
![d=s\times t](https://tex.z-dn.net/?f=d%3Ds%5Ctimes%20t)
![d=\dfrac{c}{n_w}\times \dfrac{3\times10^{-3}\times1.517}{c}](https://tex.z-dn.net/?f=d%3D%5Cdfrac%7Bc%7D%7Bn_w%7D%5Ctimes%20%5Cdfrac%7B3%5Ctimes10%5E%7B-3%7D%5Ctimes1.517%7D%7Bc%7D)
![d=\dfrac{3\times10^{-3}\times 1.517}{1.333}](https://tex.z-dn.net/?f=d%3D%5Cdfrac%7B3%5Ctimes10%5E%7B-3%7D%5Ctimes%201.517%7D%7B1.333%7D)
d = 3.41 mm
Is balancing .
Hope this is helpful