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goblinko [34]
3 years ago
5

Give me an example of the product rule

Mathematics
1 answer:
ad-work [718]3 years ago
3 0

Answer:

A simple example: Say that f(x) is x+1 and g(x) is x^2. While f(x)g(x) would be (x+1)x^2, f of g of x would be x^2+1. Continuing on with the same example, the f(x)g(x) derivative with the product rule would give x^2+2x(x+1), and the f of g of x derivative would be 2x.

Step-by-step explanation:

Really hope this could help - Good luck and have a nice day ^w

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8 0
3 years ago
Read 2 more answers
After an earthquake, 1/4 of all claims were paid within a month. Of the remaining claims that had not yet been paid, 4/7
eduard

Answer:

16/28 claims

Step-by-step explanation:

7/28

16/28

- You need to find common denominator. (use 28)

- If you would like a further explanation please let me know.

4 0
3 years ago
Round 519.6597 to the nearest tenth place
EleoNora [17]
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8 0
4 years ago
Find the average rate of change of the function over the given interval
sattari [20]
\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\

\bf h(t)=cot(t)\implies h(t)=\cfrac{cos(t)}{sin(t)}\quad 
\begin{cases}
t_1=\frac{\pi }{4}\\
t_2=\frac{3\pi }{4}
\end{cases}\implies \cfrac{h\left( \frac{3\pi }{4} \right)-h\left( \frac{\pi }{4} \right)}{\frac{3\pi }{4}-\frac{\pi }{4}}
\\\\\\

\bf \cfrac{\frac{cos\left( \frac{3\pi }{4} \right)}{sin\left( \frac{3\pi }{4} \right)}-\frac{cos\left( \frac{\pi }{4} \right)}{sin\left( \frac{\pi }{4} \right)}}{\frac{\pi }{2}}\implies \cfrac{-1-1}{\frac{\pi }{2}}\implies \cfrac{-2}{\frac{\pi }{2}}\implies -\cfrac{4}{\pi }\\\\\\
-------------------------------\\\\

\bf h(t)=cot(t)\implies h(t)=\cfrac{cos(t)}{sin(t)}\quad 
\begin{cases}
t_1=\frac{\pi }{3}\\
t_2=\frac{3\pi }{2}
\end{cases}\implies \cfrac{h\left( \frac{3\pi }{2} \right)-h\left( \frac{\pi }{3} \right)}{\frac{3\pi }{2}-\frac{\pi }{3}}
\\\\\\

\bf \cfrac{\frac{cos\left( \frac{3\pi }{2} \right)}{sin\left( \frac{3\pi }{2} \right)}-\frac{cos\left( \frac{\pi }{3} \right)}{sin\left( \frac{\pi }{3} \right)}}{\frac{9\pi -2\pi  }{6}}\implies \cfrac{\frac{0}{-1}-\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}}{\frac{7\pi }{6}}\implies\cfrac{-\frac{1}{\sqrt{3}}}{\frac{7\pi }{6}}\implies -\cfrac{\sqrt{3}}{3}\cdot \cfrac{6}{7\pi }
\\\\\\
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8 0
4 years ago
If x-5/4 = -9/5, then x =
Lerok [7]

Answer:

[See Below]

Step-by-step explanation:

✦ First change the improper fractions to decimals:

  ✧ ⁵⁄₄ = 1.25

  ✧ -⁹⁄₅ = -1.8

✦ Then divide:

  ✧ 1.25 ÷ -1.8 = -0.69

So x would be -0.69 in decimal form.

~<em>Hope this helps Mate. If you need anything feel free to message me.</em>

8 0
4 years ago
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