Assume ladder length is 14 ft and that the top end of the ladder is 5 feet above the ground.
Find the distance the bottom of the ladder is from the base of the wall.
Picture a right triangle with hypotenuse 14 feet and that the side opposite the angle is h. Then sin theta = h / 14, or theta = arcsin 5/14. theta is
0.365 radian. Then the dist. of the bot. of the lad. from the base of the wall is
14cos theta = 14cos 0.365 rad = 13.08 feet. This does not seem reasonable; the ladder would fall if it were already that close to the ground.
Ensure that y ou have copied this problem accurately from the original.
Answer:
Step-by-step explanation:
This is a simple proportion problems.
7 kilogram weight attache to a spring stretches = 6 meters
1 kilogram would stretch = 6/7 m
Therefore 42 kilograms would stretch = (6/7 x 42)meters
= 36 meters.
Answer:
720 in^3.
Step-by-step explanation:
12 * 60 = 720.
Answer: 1-91,1-42,101,161
The longest meter is 3.35
