The answer is 4m+8n-4p.
What is the surface area? 5 mm 4 mm 5 mm 6 mm 6 mm square millimeters
1 answer:
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The solutions appear to be {π/2, 2π/3, 4π/3}.
_____
Replacing sin(2x) with 2sin(x)cos(x), you have
2sin(x)cos(x) +sin(x) -2cos(x) -1 = 0
sin(x)(2cos(x) +1) -(2cos(x) +1) = 0 . . . . factor by grouping
(sin(x) -1)(2cos(x) +1) = 0
This has solutions
sin(x) = 1
x = π/2
and
2cos(x) = -1
cos(x) = -1/2
x = {2π/3, 4π/3}
_____
Replacing sin(2x) with 2sin(x)cos(x), you have
2sin(x)cos(x) +sin(x) -2cos(x) -1 = 0
sin(x)(2cos(x) +1) -(2cos(x) +1) = 0 . . . . factor by grouping
(sin(x) -1)(2cos(x) +1) = 0
This has solutions
sin(x) = 1
x = π/2
and
2cos(x) = -1
cos(x) = -1/2
x = {2π/3, 4π/3}
Answer: Our required interval for temperature is
Step-by-step explanation:
Since we have given that
The normal temperature range for Yuma, on Janurary is atleast = 48 degrees
and the highest temperature on that day is no higher than 64 degrees.
Let the temperature in Yuma be 'x'.
So, we know that for atleast means it can 48 degrees or more, and no higher than means it should be equa to or less than 64 degrees.
Mathematically, it is expressed as
Hence, our required interval for temperature is