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lord [1]
3 years ago
15

What is the answer to (-3a²b²c⁴)³

Mathematics
1 answer:
aleksandrvk [35]3 years ago
6 0
The answer is -27a^6b^6c^12
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You invested $52.400 at 6% compounded annually for 5 years. What is your total return on this investment
Tems11 [23]

Answer:

$15,720

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

Simple Interest Rate Formula: A = P(1 + rt)

  • <em>P</em> is principle amount
  • <em>r</em> is rate
  • <em>t</em> is time

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify variables.</em>

<em>P</em> = $52,400

<em>r</em> = 6%

<em>t</em> = 5

<u>Step 2: Find Current Investment Value</u>

  1. Substitute in variables [Simple Interest Rate Formula]:                                 A = 52,400(1 + 0.06 · 5)
  2. [Order of Operations] Evaluate:                                                                      A = $68,120

<u>Step 3: Find Total Return</u>

  1. Set up:                                                                                                               R = A - P
  2. Substitute in variables:                                                                                     R = 68,120 - 52,400
  3. [Order of Operations] Evaluate:                                                                      R = $15,720
5 0
3 years ago
"My friend here Justin, he's already taken, and he's cracked at Fortnite my guy.
Fynjy0 [20]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Select all radical expressions that are equivalent to 347. (3√4)7 (3√7)4 21−−√4 37−−√4 81−−√7 12−−√7
vichka [17]

Answer:

can you add the answer choices please? thank you!

Step-by-step explanation:

4 0
3 years ago
Find the equation of a line that passes through the points (-1,-3) and (1,-5).
Cerrena [4.2K]

Answer:

Y= -1x - 4

Step-by-step explanation:

4 0
3 years ago
National data in the 1960's showed that about 44% of the adult population had never smoked cigarettes. In 1995 a national health
Marta_Voda [28]

Answer:

a) 0.52 - 1.96\sqrt{\frac{0.52(1-0.52)}{881}}=0.487

0.52 + 1.96\sqrt{\frac{0.52(1-0.52)}{881}}=0.553

The 95% confidence interval would be given by (0.487;0.553)

b) After see the confidence interval we see that the lower limits 0.487>0.44 with 0.44 or 44% the estimated  proportion for 1960, we can conclude that we have a significant increase in the adult proportion had never smoked cigarettes.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.52 - 1.96\sqrt{\frac{0.52(1-0.52)}{881}}=0.487

0.52 + 1.96\sqrt{\frac{0.52(1-0.52)}{881}}=0.553

The 95% confidence interval would be given by (0.487;0.553)

Part b

After see the confidence interval we see that the lower limits 0.487>0.44 with 0.44 or 44% the estimated  proportion for 1960, we can conclude that we have a significant increase in the adult proportion had never smoked cigarettes at 5% of significance.

4 0
4 years ago
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