Answer:
61.64 cm
Step-by-step explanation:
The longest metal rod which could be stored in a rectangular box will be equal to its diagonal:
2(x + 3) = x - 4
distribute
2x + 6 = x - 4
either subtract 6 from both sides or add 4. i will be subtracting 6.
2x = x - 10
subtract x from both sides
x = -10
Answer:
A. a = 10
B. m<FNT = 120°
C. m<KTU = 60°
Step-by-step explanation:
A. (7a + 50)° and (14a - 20)° are corresponding angles. Therefore:
(7a + 50)° = (14a - 20)°
Use this equation to find the value of a
7a + 50 = 14a - 20
Combine like terms
7a - 14a = - 50 - 20
-7a = -70
Divide both sides by -7
-7a/-7 = -70/-7
a = 10
B. m<FNT = (14a - 20)° (alternate interior angles are congruent)
Plug in the value of a
m<FNT = 14(10) - 20
m<FNT = 140 - 20
m<FNT = 120°
C. m<KTU + (14a - 20)° = 180° (linear pair)
Plug in the value of a
m<KTU + 14(10) - 20 = 180
m<KTU + 120 = 180
m<KTU + 120 - 120 = 180 - 120
m<KTU = 60°
You have a 4/ 6 chance
then you have a 2/6 chance if the number is an odd number then reducing you would get
1. 2/3
2. 1/3
<span>The side opposite the 30 degree angle is half of the hypotenuse.
a^2 + b^2 = c^2 =>
a^2 + (c/2)^2 = c^2
12^2 + c^2/4 = c^2
4*12^2 + c^2 - 4c^2 = 0
576 - 3c^2 = 0
- 3c^2 = - 576
c^2 = 192
c = 8√3
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