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3 years ago

[6+(10-8)7]+5. need help ASAP*

Mathematics

2 answers:

Sergio [31]3 years ago

8 0

Answer:

Step-by-step explanation:

Using PEMDAS, you start by evaluating the expression in parentheses:

(6 + (2) × 7 ) + 5

Since there are no exponents, you do the multiplication/division next:

(6 + 14) + 5

Then add the rest:

(20) + 5

White raven [17]3 years ago

6 0

Step-by-step explanation:

Given

[ 6 + ( 10- 8 ) *7 ] + 5

= [ 6 + 2 * 7] + 5

= [ 6 + 14 ] + 5

= 20 + 5

= 25

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I went to the movies and bought 4 tickets. It cost me 23 dollars for the tickets after I applied my 5 dollar Tuesday discount. C

Scilla [17]

Answer:

x= 5.75$

Step-by-step explanation:

23 divided by 4 = 5.75$ (without the discount it is 10.75$)

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2 years ago

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Find the type and number of solution for g(x) = x2 -14x = -50

inysia [295]

Answer:

Step-by-step explanation:

x² -14x+50= 0

this equation has 2 solutions because is a quadratic

the solurions are imaginary roots because the discriminant is less then 0

b²-4ac = (-14)²-4*1*50 = 194-200= -6

to find the actual roots use the quadratic formula

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2 years ago

Find the numerical value of the log expression.<br> log a = 11<br> log b = -5<br> log c= 6

Anna35 [415]

Refer to the attachment for answer...

4 0

2 years ago

Apex Learning Study 4.2.1 What units do you use to report the area of a circle with a radius of 50 feet?

klasskru [66]

Answer:

<h3> in square feet</h3>

Step-by-step explanation:

Area of anything is<u> allways </u>reported <u>in square units</u>. Usually that is square of given unit because it's the simplest way:

R = 50 ft

A = πR² = π•(50 ft)² = π • 50 ft • 50 ft = 2500π ft² ≈ 7854 ft²

{Of course you can re-calculate the units, ex.:

3 feet = 1 yard so 50 ft = 50/3 yd then

A = πR² = π•(50/3 yd)² = π • 50/3 yd • 50/3 yd = 2500/9 π yd² ≈ 872.7 yd² }

3 0

2 years ago

What is the coefficient of x2y3 in the expansion of (2x + y)5?

Zigmanuir [339]

Option C:

The coefficient of $x^{2} y^{3}$ is 40.

Solution:

Given expression:

$(2 x+y)^{5}$

Using binomial theorem:

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here $a=2 x, b=y$

Substitute in the binomial formula, we get

$(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}$

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}$

$$+\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}+\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}$

Let us solve the term one by one.

$$\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}=32 x^{5}$

$$\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1} = 80 x^{4} y$

$$\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}= 80 x^{3} y^{2}$

$$\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}= 40 x^{2} y^{3}$

$$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}$

$$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}$

Substitute these into the above expansion.

$(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}$

The coefficient of $x^{2} y^{3}$ is 40.

Option C is the correct answer.

5 0

2 years ago

[6+(10-8)*7]+5. *need help ASAP*

[6+(10-8)7]+5. need help ASAP*