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2 years ago

What is the area of the rectangle?

Mathematics

1 answer:

user100 [1]2 years ago

6 0

Answer:

12,180

Step-by-step explanation:

got

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Give the following equations determine if the lines are parallel perpendicular or neither

GaryK [48]

In order to determine whether the equations are parallel, perpendicular, or neither, let's simply each equation into a slope-intercept form or basically, solve for y.

Let's start with the first equation.

$\frac{6x-5y}{2}=x+1$

Cross multiply both sides of the equation.

$6x-5y=2(x+1)$ $6x-5y=2x+2$

Subtract 6x on both sides of the equation.

$6x-5y-6x=2x+2-6x$ $-5y=-4x+2$

Divide both sides of the equation by -5.

$-\frac{5y}{-5}=\frac{-4x}{-5}+\frac{2}{-5}$ $y=\frac{4}{5}x-\frac{2}{5}$

Therefore, the slope of the first equation is 4/5.

Let's now simplify the second equation.

$-4y-x=4x+5$

Add x on both sides of the equation.

$-4y-x+x=4x+5+x$ $-4y=5x+5$

Divide both sides of the equation by -4.

$\frac{-4y}{-4}=\frac{5x}{-4}+\frac{5}{-4}$ $y=-\frac{5}{4}x-\frac{5}{4}$

Therefore, the slope of the second equation is -5/4.

Since the slope of each equation is the negative reciprocal of each other, then the graph of the two equations is perpendicular to each other.

5 0

9 months ago

Please help <br><br>y≥1/3x-3

zloy xaker [14]

Answer:

B, the one with the line and shaded the top on the right side. (The one that goes to 7 on the x axis).

Step-by-step explanation:

First I find which graph as y -intercept of -3, which is all of them.

Next, I find with graph has a slope of 1/3. (rise 1 run 3). Only B and D has a slope of 1/3 (The ones that has a less steep graph. )

Then, I use the coordinate (0,0) to see which side the graph shades. I plug it into the inequality. (0)≥1/3(0)-3. Solve. Is 0 greater than -3. YES! so we shade the part where (0,0) is shaded which is B.

6 0

2 years ago

What is the rate of change of the volume of the cylinder at that instance (in cubic kilometers per second)?

Kay [80]

Answer:

hello your question is incomplete attached below is the complete question

answer : -2400 π

Step-by-step explanation:

dr/dt = -12 km/s

h = 2.5 km

r = 40 km at some instant

hence the rate of change of Volume of cylinder at that instance

= dv / dt = $d(\pi r^h ) / dt$

= $\pi h\frac{d(r^2)}{dt}$ = $-\pi h *2r *dr/dt$

hence ; dv / dt = -2400 π

3 0

2 years ago

2/(a-7)(a+2)=4/(a+3)(a+2)

pochemuha

$\frac{2}{(a - 7)(a + 2)} = \frac{4}{(a + 3)(a + 2)}$

$\frac{2}{(a^{2} + 2a - 7a - 14)} = \frac{4}{(a^{2} + 2a + 3a + 6)}$

$\frac{2}{a^{2} - 5a - 14} = \frac{4}{a^{2} + 5a + 6}$

$2(a^{2} + 5a + 6) = 4(a^{2} - 5a - 14)$
$2(a^{2}) + 2(5a) + 2(6) = 4(a^{2}) - 4(5a) - 4(14)$
$2a^{2} + 10a + 12 = 4a^{2} - 20a - 56$
$2a^{2} - 2a^{2} + 10a + 12 = 4a^{2} - 2a^{2} - 20a - 56$
$10a + 20a + 12 = 2a^{2} - 20a + 20a - 56$
$30a + 12 + 56= 2a^{2} - 56 + 56$
$\frac{30a + 68}{2} = \frac{2a^{2}}{2}$
$15a + 34 = a^{2}$
$\sqrt{15a + 34} = a$

6 0

2 years ago

I don’t understand how to do this can anyone help

lakkis [162]

Answer:

I want to say the answer is D

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers