Answer:
5 units
Step-by-step explanation:
Let point O be the point of intersection of the kite diagonals.
|OF| = 2, |OH| = 5
|FH| = |OF| + |OH| = 2 + 5 = 7
FH and EG are the diagonals of the kite. Hence the area of thee kite is:
Area of kite EFGH = (FH * EG) / 2
Substituting:
35 = (7 * |EG|) / 2
|EG| * 7 = 70
|EG| = 10 units
The longer diagonal of a kite bisects the shorter one, therefore |GO| = |EO| = 10 / 2 = 5 units
x = |GO| = |EO| = 5 units
30 M&Ms
1) Gathering the data
12-ounce bag of trail mix = 18 M&Ms
20-ounce bag=?
2) Assuming that the M&Ms are placed in following a constant rate we can write the following proportion:
12 --------------- 18
20 --------------- y
<em>Cross multiplying it due to the first property of proportions</em>
<em />
12y =20 x 18
12y = 360
y=30
3) So, I'd expect to find 30 M&Ms at a 20-ounce bag of trail mix.
1/10 of .9 is the same as dividing .9 by 10.
.90 / 10 = .09
.09 is the answer
Answer:
The correct answer is False
Answer:
b
Step-by-step explanation:
first, group the terms with the same power together and it would become (-9n⁵-4n⁵)+(n³-9n³)+(11n+6n). then, combine the terms in each group together which would get -13n⁵-8n³+17n as the answer