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3 years ago

Solve for x, round to the nearest tenth. find x x =

Mathematics

2 answers:

Sati [7]3 years ago

5 0

Answer:

x = 64.2°

Step-by-step explanation:

tan x° = 29/14

14 · tan x° = 29

tan x° = 29/14

arctan(x) = 64.2°

Illusion [34]3 years ago

3 0

Answer:

64.2

Step-by-step explanation:

Use tan to find the measure of x.

tan = 0pposite/adjacent

opposite = 29

adjacent = 14

so:

$tan(x)=29/14\\x = tan^{-1} (29/14)\\x = 64.2$

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Find the missing terms.<br> 3, _____, _____, 21 (arithmetic)

natka813 [3]

Answer:

3, 9, 15, 21

Step-by-step explanation:

3x1=3 v

3x2=6

3x3=9 v

3x4=12

3x5=15 v

3x6=18

3x7=21 v

Skip one each time, 3, 9, 15, 21

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2 years ago

You are a truck driver for a distribution center. You drove 30 hours in 5 days. What is your per day average?

andreyandreev [35.5K]

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3 years ago

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Alja [10]

Answer:

the second answer

Step-by-step explanation:

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3 years ago

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Simplest form of 4500:80000 and 8100:144000

a_sh-v [17]

9514 1404 393

Answer:

9/160
9/160

Step-by-step explanation:

Divide each number in the ratio by their greatest common divisor.

4500 : 80000 = (4500/500) : (80000/500) = 9 : 160

8100 : 144000 = (8100/900) : (144000/900) = 9 : 160

3 0

3 years ago

The Environmental Protection Agency (EPA) has contracted with your company for equipment to monitor water quality for several la

max2010maxim [7]

Answer:

36.58% probability that one of the devices fail

Step-by-step explanation:

For each device, there are only two possible outcomes. Either it fails, or it does not fail. The probability of a device failling is independent of other devices. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A total of 15 devices will be used.

This means that $n = 15$

Assume that each device has a probability of 0.05 of failure during the course of the monitoring period.

This means that $p = 0.05$

What is the probability that one of the devices fail?

This is $P(X = 1)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{15,1}.(0.05)^{1}.(0.95)^{14} = 0.3658$

36.58% probability that one of the devices fail

7 0

2 years ago