Answer:
The picture below with the answer. Hope it helps, have a great day/night and stay safe! Length of the coil,
Answer:
6.9
Explanation:
I had the same question lol your welcomr if itd not right in sorry
78950W the answer
Explanation:
A 75- kw, 3-, Y- connected, 50-Hz 440- V cylindrical synchronous motor operates at rated condition with 0.8 p.f leading. the motor efficiency excluding field and stator losses, is 95%and X=2.5ohms. calculate the mechanical power developed, the Armature current, back e.m.f, power angle and maximum or pull out torque of the motor
A 75- kw, 3-, Y- connected, 50-Hz 440- V cylindrical synchronous motor operates at rated condition with 0.8 p.f leading. the motor efficiency excluding field and stator losses, is 95%and X=2.5ohms. calculate the mechanical power developed, the Armature current, back e.m.f, power angle and maximum or pull out torque of the motor
Answer:
A) Upper bound modulus of elasticity; E = 165.6 GPa
B) Lower bound modulus of elasticity; E = 83.09 GPa
Explanation:
A) Formula for upper bound modulus is given as;
E = E_m(1 - V_f) + E_f•V_f
We are given;
E_m = 60 GPa
E_f = 380 GPa
V_f = 33% = 0.33
Thus,
E = 60(1 - 0.33) + 380(0.33)
E = (60 x 0.67) + 125.4
E = 165.6 GPa
B) Formula for lower bound modulus is given as;
E = 1/[(V_f/E_f) + ((1 – V_f)/E_m)]
E = 1/[(0.33/380) + ((1 – 0.33)/60)]
E = 1/(0.0008684 + 0.01116667)
E = 1/0.01203507
E = 83.09 GPa
