Convert Mg to grams
1g =1000mg what about 3.91 Mg
= 3.91mg x 1g/1000mg= 3.91 x10^-3 g
moles= mass/molar mass
that is 3.91 x10^-3g /99 g/mol=3.95 x10^-5moles
concentration= moles / vol in liters
that is 3.95 x10^-5/100 x1000= 3.94 x10^-4M
equation for dissociation of CUCl= CUCl----> CU^+ +Cl^-
Ksp=(CU+)(CI-)
that is (3.95 x10^-4)(3.95 x10^-4)
Ksp= 1.56 x10^-7
Yes, It is important to know the volume of Unknown acid or base to be titrated.
Titration is carried out in order to find out the concentration (i.e. molarity) of unknown acid or base. In this process a standard solution of acid or base is taken and is titrated with known volume of of titrant. At end point (neutralization) the amount of standard titrant utilized is calculated and following formula is employed to calculate the unknown concentration of unknown solution.
M₁V₁/n₁ = M₂V₂/n₂
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