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Svetlanka [38]
3 years ago
10

The solubility of copper(i) chloride is 3.91 mg per 100.0 ml of solution. calculate ksp for cucl (cucl=99.00 g mol-1).

Chemistry
2 answers:
Damm [24]3 years ago
4 0

Answer : The value of K_{sp} is 1.56\times 10^{-7}

Explanation :

First we have to calculate the mass of CuCl in 1 L or 1000 mL solution.

As, 100.0 mL of solution contains 3.91 mg of CuCl

So, 1000 mL of solution contains \frac{1000mL}{100.0mL}\times 3.91mg=39.1mg of CuCl

The mass of CuCl = 39.1 mg = 0.0391 g

conversion used : (1 mg = 0.001 g)

Now we have to calculate the moles of CuCl.

\text{Moles of }CuCl=\frac{\text{Mass of }CuCl}{\text{Molar mass of }CuCl}

Molar mass of CuCl = 99.00 g/mol

\text{Moles of }CuCl=\frac{0.0391g}{99.00g/mol}=3.95\times 10^{-4}mole

Now we have to calculate the moles of Cu^+ and Cl^- ion.

Moles of Cu^+ = Moles of Cl^- = Moles of CuCl = 3.95\times 10^{-4}mole

Thus, the concentration of Cu^+ and Cl^- ion in 1 L solution will be:

[Cu^+] = [Cl^-] = 3.95\times 10^{-4}M

Now we have to calculate the value of K_{sp} for CuCl.

The solubility equilibrium reaction will be:

CuCl\rightleftharpoons Cu^{+}+Cl^{-}

The expression for solubility constant for this reaction will be,

K_{sp}=[Cu^{+}][Cl^{-}]

K_{sp}=(3.95\times 10^{-4})\times (3.95\times 10^{-4})

K_{sp}=1.56\times 10^{-7}

Therefore, the value of K_{sp} is 1.56\times 10^{-7}

garri49 [273]3 years ago
3 0
Convert  Mg  to  grams
1g =1000mg  what  about  3.91  Mg
=  3.91mg  x  1g/1000mg=  3.91  x10^-3 g
moles= mass/molar mass
that  is  3.91  x10^-3g  /99 g/mol=3.95 x10^-5moles
concentration=   moles  /  vol   in  liters

that  is  3.95  x10^-5/100  x1000=  3.94  x10^-4M

equation for  dissociation  of  CUCl=   CUCl---->  CU^+   +Cl^-

Ksp=(CU+)(CI-)
that  is  (3.95  x10^-4)(3.95  x10^-4)
Ksp=  1.56  x10^-7
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