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lord [1]
3 years ago
10

I don’t understand this question. picture above |||

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
6 0
If it’s stated that 400 minutes is $19.70 and how many minutes in a month do you use your phone so it would be 400
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Measure the angle and classify it as right, acute, or obtuse.Question 1 options:
IrinaK [193]
25 , acute because 25 is an acute
5 0
3 years ago
Find the circumference use 3.14 for the value of
Reil [10]

Answer:

the answer is 69.3

Step-by-step explanation:

5 0
3 years ago
ASAP plz
Ivenika [448]

Answer:

$23.85

Step-by-step explanation:

39.95 x 3 which can also be 39.95 + 39.95 + 39.95=119.85

So then do 143.70-119.85 to find the answer which is 23.85.

8 0
3 years ago
Read 2 more answers
Country A has a growth rate of 4.9​% per year. The population is currently 4 comma 151​,000, and the land area of Country A is 1
kvv77 [185]

Answer:

There will be one person on 1 square yard of land after 1,892,147.588 years.

Step-by-step explanation:

Continuous exponential growth formula:

P(t)=Pe^{rt}

P(t)= Population after t years.

P= Initial population

r=rate of growth.

t= time in year

Given that,

Growth rate of country A (r)= 4.9% per year=0.049 per year.

Initial population (P)= 151,000.

Land area of country area= 14,000,000,000 square yards.

There will be one person on one  square yard of land.

So, there will be 14,000,000,000  person for 14,000,000,000 square yard of land in country A.

P(t)=14,000,000,000 person

\therefore 14,000,000,000= 151,000 e^{0.049t}

\Rightarrow e^{0.049t}=\frac{ 14,000,000,000}{ 151,000}

Taking ln both sides

\Rightarrow ln|e^{0.049t}|=ln|\frac{ 14,000,000,000}{ 151,000}|

\Rightarrow {0.049t}=ln|\frac{ 14,000,000,000}{ 151,000}|

\Rightarrow t}=\frac{ln|\frac{ 14,000,000,000}{ 151,000}|}{0.049}

\Rightarrow t}=1,892,147.588 years

There will be one person for every square yard of land after 1,892,147.588 years.

7 0
3 years ago
Help please and thankyou <3
Serjik [45]

The answer is D, because -2/3/2 = -4/3.

8 0
4 years ago
Read 2 more answers
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