Answer:
They both have a cell membrane, however a plant also has a cell wall.
Explanation:
Moles of oxygen = mass/molar mass of O2 = 8/31.998 = 0.25 moles.
Number of particles = moles x 6.02 x 10^23 = 0.25 x 6.02 x 10^23 = 1.505 x 10^23 particles.
Hope this helps!
Answer:
11
Explanation:
Moles of KOH = 
Volume of water = 10 liters
Concentration of KOH is given by
![[KOH]=\dfrac{10^{-2}}{10}\\\Rightarrow [KOH]=10^{-3}\ \text{M}](https://tex.z-dn.net/?f=%5BKOH%5D%3D%5Cdfrac%7B10%5E%7B-2%7D%7D%7B10%7D%5C%5C%5CRightarrow%20%5BKOH%5D%3D10%5E%7B-3%7D%5C%20%5Ctext%7BM%7D)
is strong base so we have the following relation
![[KOH]=[OH^{-}]=10^{-3}\ \text{M}](https://tex.z-dn.net/?f=%5BKOH%5D%3D%5BOH%5E%7B-%7D%5D%3D10%5E%7B-3%7D%5C%20%5Ctext%7BM%7D)
![pOH=-\log [OH^{-}]=-\log10^{-3}](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E%7B-%7D%5D%3D-%5Clog10%5E%7B-3%7D)

So, pH of the solution is 11
Answer: The rate law is ![rate=k[CH_3COOC_2H_5]^1[NaOH]^1](https://tex.z-dn.net/?f=rate%3Dk%5BCH_3COOC_2H_5%5D%5E1%5BNaOH%5D%5E1)
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
For the given reaction:

k= rate constant
Rate law: ![rate=k[CH_3COOC_2H_5]^x[NaOH]^y](https://tex.z-dn.net/?f=rate%3Dk%5BCH_3COOC_2H_5%5D%5Ex%5BNaOH%5D%5Ey)
For the given rate law:
y =1 = order with respect to 
n = total order = 2
2= (x+y)
2= (x+1)
x= 1
Thus order with respect to
is 1 and rate law is : ![rate=k[CH_3COOC_2H_5]^1[NaOH]^1](https://tex.z-dn.net/?f=rate%3Dk%5BCH_3COOC_2H_5%5D%5E1%5BNaOH%5D%5E1)
No, the properties of a substance are not affected by the amount of a substance.