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Marianna [84]
3 years ago
14

Use the permutation formula to solve a problem when n = 15 and r = 4.

Mathematics
2 answers:
Zinaida [17]3 years ago
6 0
The anwser is D .........
barxatty [35]3 years ago
3 0

nPr =  \frac{n!}{(n - r)!}

15P4 =  \frac{15!}{(15 - 4)!} = \frac{15!}{11!} \\  = \frac{15 \times 14 \times 13 \times 12 \times 11!}{11!} \\ 15 \times 14 \times 13 \times 12 = 32760

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rewona [7]
Well convert 3 5/6 to 23/6 and 4 4/5 to 24/ 5
then find a multiple that both 5 and 6 have which is 30
23x5= 115 and 24x6= 144
so 115 x 144= 16560/30
16560/30 = 552 /1 so your answer is 
552
8 0
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I need help finding the Min of these numbers.
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Step-by-step explanation:

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What is the sum of 3.6 × 103 and 6.1 × 103?
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6 0
3 years ago
2x+3y= 14<br>3х - 4 y = 4<br><br>​
goldenfox [79]

The solution to given system of equations are (x, y) = (4, 2)

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

2x + 3y = 14 ---------- eqn 1

3x - 4y = 4 --------- eqn 2

We have to solve the given system of equations

We can solve the above system of equations by elimination method

<em><u>Multiply eqn 1 by 3</u></em>

3(2x + 3y = 14)

6x + 9y = 42 --------- eqn 3

<em><u>Multiply eqn 2 by 2</u></em>

2(3x - 4y = 4)

6x - 8y = 8 ----------- eqn 4

<em><u>Subtract eqn 4 from eqn 3</u></em>

6x + 9y = 42

6x - 8y = 8

( - ) --------------

9y + 8y = 42 - 8

17y = 34

<h3>y = 2</h3>

<em><u>Substitute y = 2 in eqn 1</u></em>

2x + 3(2) = 14

2x + 6 = 14

2x = 14 - 6

2x = 8

<h3>x = 4</h3>

Thus the solution to given system of equations are (x, y) = (4, 2)

5 0
3 years ago
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